python - 无法关闭 KeyboardInterrupt 上的套接字

Question

from socket import socket, AF_INET, SOCK_STREAM

sock = socket(AF_INET, SOCK_STREAM)
sock.bind(("localhost", 7777))
sock.listen(1)
while True:
    try:
        connection, address = sock.accept()
        print("connected from " + address)
        received_message = sock.recv(300)
        if not received_message:
            break
        connection.sendall(b"hello")

    except KeyBoardInterrupt:
        connection.close()

所以我试着把我的头围在套接字上，并拥有这个非常简单的脚本但出于某种原因，我无法使用 KeyboardInterrupt

终止此脚本

我如何使用 KeyboardInterrupt 终止脚本，为什么我不能使用 KeyboardInterrupt 终止脚本？

Answer 1

1. break 以退出 while 循环。没有break，循环不会结束。
2. 为了安全起见，请检查是否设置了connection。

---

from socket import socket, AF_INET, SOCK_STREAM

sock = socket(AF_INET, SOCK_STREAM)
sock.bind(("localhost", 7777))
sock.listen(1)
while True:
    connection = None # <---
    try:
        connection, address = sock.accept()
        print("connected from ", address)
        received_message = connection.recv(300)
        if not received_message:
            break
        connection.sendall(b"hello")
    except KeyboardInterrupt:
        if connection:  # <---
            connection.close()
        break  # <---

更新

• 有一个拼写错误:KeyBoardInterrupt 应该是 KeyboardInterrupt。
• sock.recv 应该是 connection.recv。