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这里有两个列表:
var list1 = new List<UserGroupMap>
{
new UserGroupMap { UserId = "1", GroupId = "1", FormGroupFlag = "1", GroupDescription = "desc1", GroupName = "g1"},
new UserGroupMap { UserId = "1", GroupId = "2", FormGroupFlag = "1", GroupDescription = "desc1", GroupName = "g1"},
new UserGroupMap { UserId = "1", GroupId = "3", FormGroupFlag = "1", GroupDescription = "desc1", GroupName = "g1"},
new UserGroupMap { UserId = "2", GroupId = "3", FormGroupFlag = "1", GroupDescription = "desc1", GroupName = "g1"}
};
var list2 = new List<UserGroupMap>
{
new UserGroupMap { UserId = "1", GroupId = "1", FormGroupFlag = "1", GroupDescription = "desc1", GroupName = "g1"},
new UserGroupMap { UserId = "1", GroupId = "2", FormGroupFlag = "1", GroupDescription = "desc1", GroupName = "g1"},
new UserGroupMap { UserId = "1", GroupId = "3", FormGroupFlag = "1", GroupDescription = "desc1", GroupName = "g1"},
new UserGroupMap { UserId = "2", GroupId = "3", FormGroupFlag = "1", GroupDescription = "desc1", GroupName = "g1"},
new UserGroupMap { UserId = "4", GroupId = "3", FormGroupFlag = "1", GroupDescription = "desc1", GroupName = "g1"},
new UserGroupMap { UserId = "3", GroupId = "3", FormGroupFlag = "1", GroupDescription = "desc1", GroupName = "g1"},
};
现在我想要的是获得一个没有重复的列表，基本上比较 list1 和 list2 只返回重复的项目。
根据示例，它应该返回的是列表 2 中的最后两项，因为它们不在列表 1 中。
最佳答案
试试这个
list2.Except(list1).Concat(list1.Except(list2));
关于c# - 如何在 C# 中比较两个 list<object> 并只保留没有重复的项目？，我们在Stack Overflow上找到一个类似的问题： https://stackoverflow.com/questions/30297972/
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0
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