c# - 忽略异步而不等待编译警告

Question

我有一个具有以下抽象方法的基本 Controller :

[HttpDelete]
public abstract Task<IHttpActionResult> Delete(int id);

在一个特定的 Controller 中，我不想实现删除，所以该方法如下所示:

public override async Task<IHttpActionResult> Delete(int id)
{
    return ResponseMessage(Request.CreateResponse(HttpStatusCode.MethodNotAllowed, new NotSupportedException()));
}

虽然上面的代码可以编译，但我收到警告:

This async method lacks 'await' operators and will run synchronously. Consider using the 'await' operator to await non-blocking API calls, or 'await Task.Run(...)' to do CPU-bound work on a background thread.

除了忽略上述警告之外，是否有更好的替代方法(即更改上面的代码)来避免出现此警告？

编辑

我将行更改为:

return await Task.Run(() => ResponseMessage(Request.CreateResponse(HttpStatusCode.MethodNotAllowed, new NotSupportedException())));

这会删除警告。但是，有更好的解决方案吗？

Answer 1

Apart from ignoring the above warning, is there a better alternative (ie. changing the code above) so that this warning doesn't occur?

另一种方法是删除 async修饰符和使用Task.FromResult返回 Task<IHttpActionResult> :

public override Task<IHttpActionResult> Delete(int id)
{
    return Task.FromResult<IHttpActionResult>(
                ResponseMessage(Request.CreateResponse(
                                        HttpStatusCode.MethodNotAllowed,
                                        new NotSupportedException())));
}