Python:如何切断字符串中超过2个相等字符的序列

Question

我正在寻找一种有效的方法来随机生成一个字符串，以便在前 2 个字符之后截断所有超过 2 个相同字符的序列。

一些输入->输出的例子是:

hellooooooooo -> helloo
woooohhooooo -> woohhoo

我目前正在遍历字符，但速度有点慢。有没有人有其他解决方案(正则表达式或其他东西)

编辑:当前代码:

word_new = ""
        for i in range(0,len(word)-2):    
            if not word[i] == word[i+1] == word[i+2]:
                word_new = word_new+word[i]
        for i in range(len(word)-2,len(word)):
            word_new = word_new + word[i]

Answer 1

编辑:应用有用的评论后

import re

def ReplaceThreeOrMore(s):
    # pattern to look for three or more repetitions of any character, including
    # newlines.
    pattern = re.compile(r"(.)\1{2,}", re.DOTALL) 
    return pattern.sub(r"\1\1", s)

---

(此处为原始回复)尝试这样的事情:

import re

# look for a character followed by at least one repetition of itself.
pattern = re.compile(r"(\w)\1+")

# a function to perform the substitution we need:
def repl(matchObj):
   char = matchObj.group(1)
   return "%s%s" % (char, char)

>>> pattern.sub(repl, "Foooooooooootball")
'Football'