python - 使用 Openpyxl 将边框应用于单元格范围

Question

我正在使用 python 2.7.10 和 openpyxl 2.3.2，我是 Python 新手。

我正在尝试将边框应用于 Excel 工作表中指定范围的单元格(例如 C3:H10)。我的以下尝试失败并显示以下消息:

AttributeError: 'Cell' object has no attribute 'styles'.

如何为单元格添加边框？如有任何见解，我们将不胜感激。

我当前的代码:

import openpyxl
from openpyxl.styles import Border, Side

def set_border(ws, cell_range):
    rows = ws.iter_rows(cell_range)
    for row in rows:
        row[0].styles.borders = Border(left=Side(border_style='thin', color="FF000000"))
        row[-1].styles.borders = Border(right=Side(border_style='thin', color="FF000000"))
    for c in rows[0]:
        c.styles.borders = Border(top=Side(border_style='thin', color="FF000000"))
    for c in rows[-1]:
        c.styles.borders = Border(bottom=Side(border_style='thin', color="FF000000"))


# Example call to set_border
wb = openpyxl.load_workbook('example.xlsx')
ws = wb.get_sheet_by_name('Sheet1')

set_border(ws, "B3:H10")

Answer 1

首先，所有属性称为 style(不是 styles)和 border(不是 borders)。另外，要更改边框，您应该直接设置 cell.border。

除了您在边界逻辑方面存在一些问题之外，由于迭代器和角的存在，使其正常工作更加复杂。这是一个粗略的版本(它尽可能简单，但内存效率不高):

def set_border(ws, cell_range):
    rows = ws[cell_range]
    side = Side(border_style='thin', color="FF000000")

    rows = list(rows)  # we convert iterator to list for simplicity, but it's not memory efficient solution
    max_y = len(rows) - 1  # index of the last row
    for pos_y, cells in enumerate(rows):
        max_x = len(cells) - 1  # index of the last cell
        for pos_x, cell in enumerate(cells):
            border = Border(
                left=cell.border.left,
                right=cell.border.right,
                top=cell.border.top,
                bottom=cell.border.bottom
            )
            if pos_x == 0:
                border.left = side
            if pos_x == max_x:
                border.right = side
            if pos_y == 0:
                border.top = side
            if pos_y == max_y:
                border.bottom = side

            # set new border only if it's one of the edge cells
            if pos_x == 0 or pos_x == max_x or pos_y == 0 or pos_y == max_y:
                cell.border = border