c# - Linq 和异步 Lambda

Question

下面的代码...

using System;
using System.Linq;
using System.Threading.Tasks;

namespace ConsoleAsync
{
    class Program
    {
        static void Main(string[] args)
        {
            MainAsync(args).Wait();
            Console.ReadLine();
        }

        static async Task MainAsync(string[] args)
        {
            int[] test = new[] { 1, 2, 3, 4, 5 };

            if (test.Any(async i => await TestIt(i)))
                Console.WriteLine("Contains numbers > 3");
            else
                Console.WriteLine("Contains numbers <= 3");
        }

        public static async Task<bool> TestIt(int i)
        {
            return await Task.FromResult(i > 3);
        }
    }
}

给你以下错误:-

CS4010: Cannot convert async lambda expression to delegate type 'Func<int, bool>'. An async lambda expression may return void, Task or Task<T>, none of which are convertible to 'Func<int, bool>'.

在线

if (test.Any(async i => await Test.TestIt(i)))

您如何使用 Async Lambdas 和 linq？

Answer 1

您不能开箱即用 LINQ。但是您可以编写一个小的扩展方法来完成这项工作:

public static class AsyncExtensions
{
    public static async Task<bool> AnyAsync<T>(
        this IEnumerable<T> source, Func<T, Task<bool>> func)
    {
        foreach (var element in source)
        {
            if (await func(element))
                return true;
        }
        return false;
    }
}

然后像这样消费它:

static async Task MainAsync(string[] args)
{
    int[] test = new[] { 1, 2, 3, 4, 5 };

    if (await test.AnyAsync(async i => await TestIt(i))
        Console.WriteLine("Contains numbers > 3");
    else
        Console.WriteLine("Contains numbers <= 3");
}

我确实觉得有点麻烦，但它达到了你的目的。