c# - 从 C# 中的 List<> 中删除 3 个最旧的元素

Question

假设我有一个对象:

public class CustomObj
{
    DateTime Date { get; set; }
    String Name { get; set; }
}

然后假设我有一个包含 20 个不同元素的列表。

var stuff = new List<CustomObj>
{
    { Date = DateTime.Now, Name = "Joe" },
    { Date = DateTime.Now.AddDays(1), Name = "Joe2" },
    { Date = DateTime.Now.AddDays(2), Name = "Joe3" },
    { Date = DateTime.Now.AddDays(3), Name = "Joe4" },
    { Date = DateTime.Now.AddDays(4), Name = "Joe5" },
    { Date = DateTime.Now.AddDays(5), Name = "Joe6" },
    { Date = DateTime.Now.AddDays(6), Name = "Joe7" },
    { Date = DateTime.Now.AddDays(7), Name = "Joe8" },
    { Date = DateTime.Now.AddDays(8), Name = "Joe9" },
    { Date = DateTime.Now.AddDays(9), Name = "Joe10" },
    { Date = DateTime.Now.AddDays(10), Name = "Joe11" }
}

如何删除最旧的 3 个元素？

stuff.RemoveAll(item => ???)

Answer 1

如果您只需要枚举项目，这将起作用:

stuff.OrderBy(item => item.Date).Skip(3);

如果你真的想要它的列表形式，你必须在之后调用 .ToList():

stuff = stuff.OrderBy(item => item.Date).Skip(3).ToList();