c# - 将此 XML 反序列化为对象的最佳方法

Question

在我见过的其他示例中，与我的类似，有一个根节点，然后是一个数组节点，然后是一堆数组项。我的问题是，我的根节点是我的数组节点，所以我看到的示例似乎对我不起作用，而且我无法更改 XML 架构。这是 XML:

<articles>  
    <article>
      <guid>7f6da9df-1a91-4e20-8b66-07ac7548dc47</guid>
      <order>1</order>
      <type>deal_abstract</type>
      <textType></textType>
      <id></id>
      <title>Abu Dhabi's IPIC Eyes Bond Sale After Cepsa Buy</title>
      <summary>Abu Dhabi's IPIC has appointed banks for a potential sterling and euro-denominated bond issue, a document showed on Wednesday, after the firm acquired Spain's Cepsa in a $5 billion deal earlier this month...</summary>
      <readmore></readmore>
      <fileName></fileName>
      <articleDate>02/24/2011 00:00:00 AM</articleDate>
      <articleDateType></articleDateType>
    </article>

    <article>
      <guid>1c3e57a0-c471-425a-87dd-051e69ecb7c5</guid>
      <order>2</order>
      <type>deal_abstract</type>
      <textType></textType>
      <id></id>
      <title>Big Law Abuzz Over New China Security Review</title>
      <summary>China’s newly established foreign investment M&amp;A review committee has been the subject of much legal chatter in the Middle Kingdom and beyond. Earlier this month, the State Council unveiled legislative guidance on…</summary>
      <readmore></readmore>
      <fileName></fileName>
      <articleDate>02/23/2011 00:00:00 AM</articleDate>
      <articleDateType></articleDateType>
    </article>  
</articles>

这是我的类(class):

public class CurrentsResultsList
{
    public Article[] Articles;
}

public class Article
{
    public string Guid { get; set; }
    public int Order { get; set; }
    public string Type { get; set; }
    public string Title { get; set; }
    public string Summary { get; set; }
    public DateTime ArticleDate { get; set; }
}

这是来自外部 API 的 XML 响应。

Answer 1

1. 将它放在 visual studio 中的 xml 中

2. 创建 xsd 模式

3. 使用:

   "C:\Program Files\Microsoft Visual Studio 8\SDK\v2.0\Bin\xsd.exe" "MyXsd.xsd" /t:lib /l:cs /c  /namespace:my.xsd /outputdir:"C:\testtttt"  
   

现在您的 C# 类已准备就绪。
你可以使用这个:

internal class ParseXML 
{
    public static xsdClass ToClass<xsdClass>(XElement ResponseXML)
    {
        return deserialize<xsdClass>(ResponseXML.ToString(SaveOptions.DisableFormatting));
    }

    private static result deserialize<result>(string XML)
    {
        using (TextReader textReader = new StringReader(XML))
        {
            XmlSerializer xmlSerializer = new XmlSerializer(typeof(result));
            return (result) xmlSerializer.Deserialize(textReader);
        }
    } 
}