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Python 请求 urlencode 不起作用?

转载 作者:太空狗 更新时间:2023-10-29 22:08:07 26 4
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编辑:我发现了问题。 #user_sex 中的 # 未通过 python 请求转换为 %23。有没有办法强制 python 请求将 # 转换为 %23 或者我只需要手动编写那部分代码?

我正在尝试制作 facebook fql 多查询。当我使用下面的 fql_url 时

fql_url = (
'https://graph.facebook.com/fql?q='
'{"user_sex":"SELECT sex FROM user WHERE uid=me()",'
'"friends":"SELECT uid, name FROM user WHERE uid IN '
'(SELECT uid2 FROM friend WHERE uid1 = me()) '
'AND not (sex in (SELECT sex FROM #user_sex)) '
' ORDER BY name"}'
'&access_token='+access_token
)

然后运行requests.get(fql_url),返回的json是

{u'error': {
u'code': 601,
u'message': u"(#601) Parser error: unexpected '{' at position 0.",
u'type': u'OAuthException'}
}

然而,当我手动编写 fql_url 时

fql_url = (
'https://graph.facebook.com/fql?q=%7B%22'
'user_sex%22:%22SELECT%20sex%20FROM%20user%20WHERE%20uid=me()%22,%22'
'friends%22:%22SELECT%20uid,%20name%20FROM%20user%20WHERE%20uid%20IN%20'
'(SELECT%20uid2%20FROM%20friend%20WHERE%20uid1%20=%20me())%20'
'AND%20not%20(sex%20in%20(select%20sex%20from%20%23user_sex))%20%20'
'ORDER%20BY%20name%22%7D&'
'access_token='+access_token
)

一切正常(json 具有所需的数据)。

我已经比较了第一个 fql_url 和手工编码的 fql_url,两者应该会导致使用相同的 url 来获取 json。是请求 urlencode 不起作用还是我在这里做错了什么?

最佳答案

问题是,# 确实是 URL 中的有效字符。它表示片段部分。由于片段总是由用户代理解析,因此它永远不会发送到服务器。你可以试试这个:

>>> import urllib3
>>> urllib3.util.parse_url(fql_url)
Url(scheme='https', auth=None, host='graph.facebook.com', port=None, path='/fql',
query='q={"user_sex":"SELECT sex FROM user WHERE uid=me()","friends":"SELECT uid, name FROM user WHERE uid IN (SELECT uid2 FROM friend WHERE uid1 = me()) AND not (sex in (SELECT sex FROM ',
fragment='user_sex)) ORDER BY name"}')

如您所见,URL 的最后一部分最终被解析为片段。

编辑:

最方便的方法可能是让请求完成所有编码。

import requests
s = requests.Session()
s.params = {'access_token': 'foobarbaz'} # so you don't have to specify it every time
query = ('{"user_sex":"SELECT sex FROM user WHERE uid=me()",'
'"friends":"SELECT uid, name FROM user WHERE uid IN '
'(SELECT uid2 FROM friend WHERE uid1 = me()) '
'AND not (sex in (SELECT sex FROM #user_sex)) '
' ORDER BY name"}')
s.get('https://graph.facebook.com/fql', params={'q': query})

关于Python 请求 urlencode 不起作用?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/17375624/

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