python - 如何在 Python 中获取文件的内容类型？ (带网址..)

Question

假设我有一个视频文件:

http://mydomain.com/thevideofile.mp4

如何获取此文件的标题和内容类型？用 python 。但是，我不想下载整个文件。我希望它返回:

video/mp4

编辑:这就是我所做的。你怎么看？

f = urllib2.urlopen(url)
    params['mime'] =  f.headers['content-type']

Answer 1

像这样:

>>> import httplib
>>> conn = httplib.HTTPConnection("mydomain.com")
>>> conn.request("HEAD", "/thevideofile.mp4")
>>> res = conn.getresponse()
>>> print res.getheaders()

这只会下载并打印标题，因为它正在制作 HEAD要求:

Asks for the response identical to the one that would correspond to a GET request, but without the response body. This is useful for retrieving meta-information written in response headers, without having to transport the entire content.

(通过 Wikipedia )