c# - 如何创建泛型方法以返回调用指定的特定类型？

Question

以下代码给出了错误:

Cannot implicitly convert type T to string.
Cannot implicitly convert type T to int.

我必须怎么做才能让这个方法在我调用它时返回我用 T 定义的变量类型？

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;

namespace TestGener234
{
    class Program
    {
        static void Main(string[] args)
        {
            Console.WriteLine("his first name is {0}", GetPropertyValue<string>("firstName"));
            Console.WriteLine("his age is {0}", GetPropertyValue<int>("age"));
        }

        public static T GetPropertyValue<T>(string propertyIdCode)
        {
            if (propertyIdCode == "firstName")
                return "Jim";
            if (propertyIdCode == "age")
                return 32;
            return null;
        }
    }
}

附录:

这是一个更完整的示例，说明了为什么我需要通用解决方案，即我有一个类，无论类型如何，它都将其值保存为字符串，而这个通用解决方案只是让调用代码更清晰:

using System;
using System.Collections.Generic;

namespace TestGener234
{
    class Program
    {
        static void Main(string[] args)
        {
            List<Item> items = Item.GetItems();
            foreach (var item in items)
            {
                string firstName = item.GetPropertyValue<string>("firstName");
                int age = item.GetPropertyValue<int>("age");
                Console.WriteLine("First name is {0} and age is {1}.", firstName, age);
            }
            Console.ReadLine();
        }
    }

    public class Item
    {
        public string FirstName { get; set; }
        public string Age { get; set; }


        public static List<Item> GetItems()
        {
            List<Item> items = new List<Item>();
            items.Add(new Item { FirstName = "Jim", Age = "34" });
            items.Add(new Item { FirstName = "Angie", Age = "32" });
            return items;
        }

        public T GetPropertyValue<T>(string propertyIdCode)
        {
            if (propertyIdCode == "firstName")
                return (T)(object)FirstName;
            if (propertyIdCode == "age")
                return (T)(object)(Convert.ToInt32(Age));
            return default(T);
        }
    }
}

Answer 1

那就麻烦了；为了使编译器满意，您可以进行双重转换，但这意味着值类型有一个框:

    public static T GetPropertyValue<T>(string propertyIdCode)
    {
        if (propertyIdCode == "firstName")
            return (T)(object)"Jim";
        if (propertyIdCode == "age")
            return (T)(object)32;
        return default(T);
    }

实际上，我认为您最好只使用 object 返回类型。