python 套接字得到

Question

从其他关于 stack overflow 的帖子来看，这应该是可行的

import socket

s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)                 

s.connect(("www.cnn.com" , 80))
s.sendall("GET / HTTP/1.1\r\n")
print s.recv(4096)
s.close

但由于某种原因它只是挂起(在 recv)并且从不打印。我知道对 www.cnn.com 的请求会将其数据分 block ，但我至少应该从 recv 中读取一些内容，对吗？

p.s. I know this isn't the best way to do it and that there are library like httplib and urllib2 out there, but I can't use those for this project (it's for school). I have to use the socket library

Answer 1

您忘记在请求行后发送一个空行:

s.sendall("GET / HTTP/1.1\r\n\r\n")

此外，HTTP 1.1 指定您应该添加 Host header 字段，如 Host section in the HTTP 1.1 RFC 中所述.

s.sendall("GET / HTTP/1.1\r\nHost: www.cnn.com\r\n\r\n")