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c# - 带有poco生成的 Entity Framework IQueryable

转载 作者:太空狗 更新时间:2023-10-29 22:01:01 27 4
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我创建了一个 T4 模板,它生成标准实体类及其每个属性的接口(interface),这样我就可以制作仅包含我想要的数据的自定义 poco 对象。我还创建了一个复制函数,它可以在实现所述实体接口(interface)的任何对象之间进行转换

生成的代码如下所示

//------------------------------------------------------------------------------
// <auto-generated>
// This code was generated from a template.
//
// Manual changes to this file may cause unexpected behavior in your application.
// Manual changes to this file will be overwritten if the code is regenerated.
// </auto-generated>
//------------------------------------------------------------------------------

namespace DomainModel
{
using System;
using System.Collections.Generic;
using System.Linq;


public interface IRole
{
}
public interface IRole_RoleId : IRole
{
int RoleId { get; set; }
}
public interface IRole_ApplicationName : IRole
{
string ApplicationName { get; set; }
}
public interface IRole_RoleName : IRole
{
string RoleName { get; set; }
}
public interface IRole_Description : IRole
{
string Description { get; set; }
}

public interface IRole_Users : IRole
{
ICollection<IUser> Users { get; set; }
IUser NewUsers();
}

public interface IRole__All : IRole_RoleId,
IRole_ApplicationName,
IRole_RoleName,
IRole_Description,
IRole_Users
{
}

public partial class Role : IRole
{
public Role()
{
this.Users = new HashSet<User>();
}

public int RoleId { get; set; }
public string ApplicationName { get; set; }
public string RoleName { get; set; }
public string Description { get; set; }

public virtual ICollection<User> Users { get; set; }
}

public static class IRoleExt
{
public static T CopyTo<T>(this IRole src , T dest = null ) where T : class, IRole, new()
{
dest = dest ?? new T();
dest.Copy(src);
return dest;
}
public static void Copy(this IRole dest, IRole src)
{
var ms = new MergeStack();
Role role;
if((role = dest as Role) != null){
ms.TryCopy<IRole,Role>((indexCopy) => {return indexCopy(role);}, src);
}
else if ((role = src as Role) != null){
ms.TryCopy<Role,IRole>((indexCopy) => {return indexCopy(dest);}, role);
}
else{
ms.TryCopy<IRole,IRole>((indexCopy) => {return indexCopy(dest);}, src);
}
dest.Copy(src, ms);
}

internal static void Copy(this IRole dest,
IRole src,
MergeStack ms)
{
dest.Set_RoleId(src.Get_RoleId());
dest.Set_ApplicationName(src.Get_ApplicationName());
dest.Set_RoleName(src.Get_RoleName());
dest.Set_Description(src.Get_Description());
dest.Set_Users(src.Get_Users(),ms);
}
public static Nullable<int> Get_RoleId(this IRole src)
{
IRole_RoleId srcIRole_RoleId;
if((srcIRole_RoleId = src as IRole_RoleId) != null )
{
return srcIRole_RoleId.RoleId;
}
Role role;
if((role = src as Role) != null )
{
return role.RoleId;
}
return null;

}
public static void Set_RoleId(this IRole dest, Nullable<int> src)
{
IRole_RoleId destIRole_RoleId;
if((destIRole_RoleId = dest as IRole_RoleId) != null)
{
destIRole_RoleId.RoleId = src.GetValueOrDefault();
}
Role role;
if((role = dest as Role) != null )
{
role.RoleId = src.GetValueOrDefault();
}
}

public static string Get_ApplicationName(this IRole src)
{
IRole_ApplicationName srcIRole_ApplicationName;
if((srcIRole_ApplicationName = src as IRole_ApplicationName) != null )
{
return srcIRole_ApplicationName.ApplicationName;
}
Role role;
if((role = src as Role) != null )
{
return role.ApplicationName;
}
return null;

}
public static void Set_ApplicationName(this IRole dest, string src)
{
IRole_ApplicationName destIRole_ApplicationName;
if((destIRole_ApplicationName = dest as IRole_ApplicationName) != null)
{
destIRole_ApplicationName.ApplicationName = src;
}
Role role;
if((role = dest as Role) != null )
{
role.ApplicationName = src;
}
}

public static string Get_RoleName(this IRole src)
{
IRole_RoleName srcIRole_RoleName;
if((srcIRole_RoleName = src as IRole_RoleName) != null )
{
return srcIRole_RoleName.RoleName;
}
Role role;
if((role = src as Role) != null )
{
return role.RoleName;
}
return null;

}
public static void Set_RoleName(this IRole dest, string src)
{
IRole_RoleName destIRole_RoleName;
if((destIRole_RoleName = dest as IRole_RoleName) != null)
{
destIRole_RoleName.RoleName = src;
}
Role role;
if((role = dest as Role) != null )
{
role.RoleName = src;
}
}

public static string Get_Description(this IRole src)
{
IRole_Description srcIRole_Description;
if((srcIRole_Description = src as IRole_Description) != null )
{
return srcIRole_Description.Description;
}
Role role;
if((role = src as Role) != null )
{
return role.Description;
}
return null;

}
public static void Set_Description(this IRole dest, string src)
{
IRole_Description destIRole_Description;
if((destIRole_Description = dest as IRole_Description) != null)
{
destIRole_Description.Description = src;
}
Role role;
if((role = dest as Role) != null )
{
role.Description = src;
}
}

public static ICollection<IUser> Get_Users(this Role src)
{
return src.Users.Cast<IUser>().ToList();
}
public static ICollection<IUser> Get_Users(this IRole src)
{
IRole_Users srcIRole_Users;
if((srcIRole_Users = src as IRole_Users) != null )
{
return srcIRole_Users.Users;
}
Role role;
if((role = src as Role) != null )
{
return role.Get_Users();
}
return null;
}
public static void Set_Users(this IRole dest, ICollection<IUser> src)
{
var ms = new MergeStack();
dest.Set_Users(src, ms);
}

internal static void Set_Users(this IRole dest, ICollection<IUser> src, MergeStack ms)
{
IRole_Users destIRole_Users;
if((destIRole_Users = dest as IRole_Users) != null)
{
Func<IUser,IUser> iToIFunc = (x=>
ms.TryCopy<IUser,IUser>((indexCopy)=>
{
var ret = destIRole_Users.NewUsers();
var exists = indexCopy(ret);
if(null != exists)
ret = exists;
else
ret.Copy(x,ms);
return ret;
},x));
destIRole_Users.Users = (null !=src)?
src.Select(iToIFunc).ToList():null;
}

Role role;
if((role = dest as Role) != null)
{
Func<IUser,User> iToEFunc = (x=>
ms.TryCopy<IUser,User>((indexCopy)=>
{
var ret = new User();
var exists = indexCopy(ret);
if(null != exists)
ret = exists;
else
ret.Copy(x,ms);
return ret;
},x));
role.Users = (null !=src)?
src.Select(iToEFunc).ToList():null;
}
}
}
}

您看到的那个合并堆栈对象是一个跟踪器,因此我可以处理引用循环。看起来像这样

using System;
using System.Collections.Generic;
using System.Linq;

namespace DomainModel
{

internal class MergeStack
{
private readonly Dictionary<Type, Dictionary<Object, Object>> _mergeObjDict = new Dictionary<Type, Dictionary<object, object>>();
private readonly IList<Action> _registerActions = new List<Action>();

public T TryCopy<TKey, T>(Func<Func<T, T>, T> func, TKey key) where T : class
{
if (key == null)
return null;

Func<T, T> act = (objToIndex) =>
{
Dictionary<object, object> objToObj;
if (!_mergeObjDict.ContainsKey(objToIndex.GetType()))
{
objToObj = new Dictionary<object, object>();
_mergeObjDict.Add(objToIndex.GetType(), objToObj);
}
else
{
objToObj = _mergeObjDict[objToIndex.GetType()];
}
if (!objToObj.ContainsKey(key))
{
objToObj.Add(key, objToIndex);
}
else
{
return objToObj[key] as T;
}
return null as T;
};
return func(act);
}
}
}

现在所有这些都按预期正常工作,它成功地将所有已实现的属性复制到域模型/接口(interface)或从域模型/接口(interface)复制。

我现在正尝试使用 IQueryable 和延迟加载。

我现在正在做这个

dbContext.Roles.Select((x)=> x.CopyTo<RolesPoco>());

我想看看是否有一种方法可以自动生成包含,例如

dbContext.Roles.Select((x)=> x.Users.Include((y)=> y.someSubEntity);

我也想看看我是否可以加入一些像这样的 where 子句

//the first string is a path so something like "Roles.Users.someSubEntity"
//the second string is a IQueryable function like Where or Take
Dictionary<String,Dictionary<String,List<Func<T, IQueryable<TProperty>>>> queryDict

dbContext.Roles.Select((x)=> x.CopyTo<RolesPoco>(queryDict)

然后 List 将是一些可以在 include 函数内部运行的 lambda 列表。有人对此有任何想法吗?

编辑:我重构并简化了一些代码,这样即使类没有实现接口(interface),它也可以调用 getter/setter。因此,无论是否存在支持字段,都可以访问属性。如果未定义,则返回 null。

Edit2:由于似乎不清楚我要实现的目标,让我澄清一下。如果您查看此 msdn page 的备注部分,您会看到一些选择语句。我想生成这些表达式,然后根据要复制到的类是否包含实现该成员的接口(interface),在父选择中使用它们。我避免使用 linqToObject,因为我只需要在 CopyTo 中定义的属性,但导航属性是接口(interface),这会破坏 Entity Framework 。这是为了延迟加载目的。 MergeStack 将组合这些表达式并将其返回到树中。我的想法来自 a DaedTech blogpost

最佳答案

Roles 是 IQueryable,因此您需要从 Queryable 扩展类中获取 Select 方法。您还需要从 Enumerable 扩展类中获取 Include。然后,您需要使用 Role 作为通用参数来调用 Select 方法。您需要使用 Expression.Lambda、Expression.Call 和 Expression.Property 构造一个 lambda。

关于c# - 带有poco生成的 Entity Framework IQueryable,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/21565703/

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