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python - 使用python查找适合文件中像素的物理坐标

转载 作者:太空狗 更新时间:2023-10-29 21:46:21 26 4
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我想从 python 脚本中获取给定像素的物理天空坐标。我想使用 astropy 的 WCS,但我会在 python 中做任何事情。

我已经尝试了这两个代码片段。

from astropy.io import fits
from astropy.wcs import WCS

def astropymethod1(img):
# from http://astropy.readthedocs.org/en/latest/wcs/
w = WCS(img)
lon, lat = w.all_pix2world( 100., 100., 1)
print lon, lat

def astropymethod2(img):
# from http://astropy.readthedocs.org/en/latest/wcs/
hdu = fits.open(img)
w = WCS(hdu[0].header)
lon, lat = w.wcs_pix2world(100., 100., 1)
print lon, lat

问题是我第一次尝试使用 WCS 时遇到错误,结果只是我输入的像素值。

WARNING: FITSFixedWarning: The WCS transformation has more axes (2) than the image it is associated with (0) [astropy.wcs.wcs]

最佳答案

问题是您有一个多扩展名的 FITS 文件。下面是一个示例 session ,展示了如何访问适当的 WCS:

In [1]: from astropy.io import fits

In [2]: h = fits.getheader('SN1415_F625W_1_drz.fits')

In [3]: f = fits.open('SN1415_F625W_1_drz.fits')

In [4]: f
Out[4]:
[<astropy.io.fits.hdu.image.PrimaryHDU at 0x106735490>,
<astropy.io.fits.hdu.image.ImageHDU at 0x106749750>,
<astropy.io.fits.hdu.image.ImageHDU at 0x106751310>,
<astropy.io.fits.hdu.image.ImageHDU at 0x106751d10>,
<astropy.io.fits.hdu.table.BinTableHDU at 0x1067dfdd0>]

In [5]: from astropy import wcs

In [6]: w = wcs.WCS(f[0].header)
WARNING: FITSFixedWarning: The WCS transformation has more axes (2) than the image it is associated with (0) [astropy.wcs.wcs]

In [7]: w.wcs.naxis
Out[7]: 2

In [8]: f[0].data

In [9]: w = wcs.WCS(f[1].header)

In [10]: w.wcs.naxis
Out[10]: 2

In [11]: f[1].data
Out[11]:
array([[ 0.01986978, -0.04018363, 0.03330525, ..., 0. ,
0. , 0. ],
[ 0.0695872 , -0.00979143, 0.00147662, ..., 0. ,
0. , 0. ],
[-0.09292094, 0.02481506, -0.01057338, ..., 0. ,
0. , 0. ],
...,
[ 0. , 0. , 0. , ..., 0.02375774,
0.0389731 , 0.03825707],
[ 0. , 0. , 0. , ..., -0.01570918,
-0.01053802, 0.00461219],
[ 0. , 0. , 0. , ..., -0.0638448 ,
-0.0240754 , 0.02679451]], dtype=float32)

In [12]: w.wcs_pix2world(100., 100., 1)
Out[12]: [array(6.113076380801787), array(0.616758775753701)]

所以你可能想重新定义你的方法:

def astropymethod2(img, hduid=1):
# from http://astropy.readthedocs.org/en/latest/wcs/
hdu = fits.open(img)
w = WCS(hdu[hduid].header)
lon, lat = w.wcs_pix2world(100., 100., 1)
print lon, lat

关于python - 使用python查找适合文件中像素的物理坐标,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/24943071/

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