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c++ - 将任意数量的类型插入到一组模板参数中

转载 作者:太空狗 更新时间:2023-10-29 21:41:27 25 4
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InsertTypes<Pack, P<Ts...>, Is...>::type是类型为 Ts... 的包插入位置Is... , 分别。例如,

InsertTypes<Pack<int, double, char, long, int>, Pack<short, float, std::string>, 2,4,1>::type,

Pack<int, std::string, double, short, char, long, float, int

(在 double 和 char 之间插入 short,在 long 和 int 之间插入 float,在 int 和 double 之间插入 std::string)。

我的方法:对 Is... 进行排序首先按相反顺序(从大到小),并为 Ts... 中的每种类型应用 Insert和 Is... 中的每个整数为什么反向排序 Is... ?因为如果它们的顺序不对,插入一个类型会使位置偏移一个并弄乱其他插入。但是我的计划有一个缺陷,稍后我会解释。首先让我提供我编写的辅助函数,我测试过它们可以独立正常工作:

Insert<T, P<Types...>, N>::type是包P<Types...> T插入位置N。

template <typename, typename, typename, int> struct InsertHelper;

template <typename T, template <typename...> class P, typename First, typename... Rest, typename... Accumulated>
struct InsertHelper<T, P<First, Rest...>, P<Accumulated...>, 0> {
using type = P<Accumulated..., T, First, Rest...>;
};

template <typename T, template <typename...> class P, typename First, typename... Rest, typename... Accumulated, int N>
struct InsertHelper<T, P<First, Rest...>, P<Accumulated...>, N> : InsertHelper<T, P<Rest...>, P<Accumulated..., First>, N-1> {};

template <typename, typename, int> struct Insert;

template <typename T, template <typename...> class P, typename... Types, int N>
struct Insert<T, P<Types...>, N> : InsertHelper<T, P<Types...>, P<>, N> {};

现在 ReverseSortIntSequence(使用快速排序):

template <int, typename> struct PrependInt;

template <int N, template <int...> class Z, int... Is>
struct PrependInt<N, Z<Is...>> {
using type = Z<N, Is...>;
};

template <template<int> class, typename> struct FilterInts;

template <template<int> class F, template <int...> class Z, int I, int... Is>
struct FilterInts<F, Z<I, Is...>> {
using type = typename std::conditional<F<I>::value,
typename PrependInt<I, typename FilterInts<F, Z<Is...>>::type>::type,
typename FilterInts<F, Z<Is...>>::type
>::type;
};

template <template<int> class F, template <int...> class Z>
struct FilterInts<F, Z<>> {
using type = Z<>;
};

template <typename, typename> struct MergeIntSequences;

template <template <int...> class Z, int... Is, int... Js>
struct MergeIntSequences<Z<Is...>, Z<Js...>> {
using type = Z<Is..., Js...>;
};

template <typename> struct ReverseSortIntSequence;

template <template <int...> class Z, int N, int... Is>
struct ReverseSortIntSequence<Z<N, Is...>> {
template<int I> struct less_than : std::integral_constant<bool, (I >= N)> {};
template <int I> struct more_than : std::integral_constant<bool, (I < N)> {};
using subsequence_less_than_N = typename FilterInts<less_than, Z<Is...>>::type;
using subsequence_more_than_N = typename FilterInts<more_than, Z<Is...>>::type;
using type = typename MergeIntSequences<typename ReverseSortIntSequence<subsequence_less_than_N>::type,
typename PrependInt<N, typename ReverseSortIntSequence<subsequence_more_than_N>::type>::type
>::type;
};

template<template <int...> class Z>
struct ReverseSortIntSequence<Z<>> {
using type = Z<>;
};

现在InsertTypes本身:

template <typename, typename, typename> struct InsertTypesHelper;

template <typename Pack, template <typename...> class P, template <int...> class Z>
struct InsertTypesHelper<Pack, P<>, Z<>> {
using type = Pack;
};

template <typename Pack, template <typename...> class P, typename First, typename... Rest, template <int...> class Z, int N, int... Ns>
struct InsertTypesHelper<Pack, P<First, Rest...>, Z<N, Ns...>> : InsertTypesHelper<typename Insert<First, Pack, N>::type, P<Rest...>, Z<Ns...>> {};

template <typename, typename, int...> struct InsertTypes;

template <typename Pack, template <typename...> class P, typename... Types, int... Is>
struct InsertTypes<Pack, P<Types...>, Is...> : InsertTypesHelper<Pack, P<Types...>, typename ReverseSortIntSequence<index_sequence<Is...>>::type> {};

现在,我的测试:

int main() {
std::cout << std::is_same<
typename ReverseSortIntSequence<index_sequence<5,10,8,4,0,2,1,2,7,8,3>>::type,
index_sequence<10,8,8,7,5,4,3,2,2,1,0>
>::value << std::endl; // true

std::cout << std::is_same<
InsertTypesHelper<Pack<int, double, char, long, int>, Pack<float, short, std::string>, index_sequence<4,2,1>>::type,
Pack<int, std::string, double, short, char, long, float, int>
>::value << std::endl; // true (*)

std::cout << std::is_same<
typename ReverseSortIntSequence<index_sequence<2,4,1>>::type,
index_sequence<4,2,1>
>::value << std::endl; // true (**)

std::cout << std::is_same<
InsertTypes<Pack<int, double, char, long, int>, Pack<short, float, std::string>, 2,4,1>::type,
Pack<int, std::string, double, short, char, long, float, int>
>::value << std::endl; // false (rats!)
}

我得到上面的错误,因为尽管上面的 (*) 和 (**) 为真,我们必须有 Pack<short, float, std::string>以与 2,4,1 相同的方式排列,以便以相反的排序顺序获得它。我可以继续进行此修复,但现在已经过火了。我仍然会继续这样做,但我严重怀疑有更好的方法,可能也很短。

这里有什么好的想法吗?我想提取索引确定的类型对(插入的类型将在对之间),但如果原始包中有重复类型(并且也因为插入的类型也一样),这将不起作用。

更新:我完成了上面讨论的排列助手,现在一切正常。但一定有比这一切困惑更好、更短的解决方案。

template <int, typename> struct NthType;

template <int N, template <typename...> class P, typename First, typename... Rest>
struct NthType<N, P<First, Rest...>> : NthType<N-1, P<Rest...>> {};

template <template <typename...> class P, typename First, typename... Rest>
struct NthType<0, P<First, Rest...>> {
using type = First;
};

template <int, int, typename> struct FindIndexOfIntHelper;

template <int N, int FindMe, template <int...> class Z, int... Rest>
struct FindIndexOfIntHelper<N, FindMe, Z<FindMe, Rest...>> : std::integral_constant<int, N> {};

template <int N, int FindMe, template <int...> class Z>
struct FindIndexOfIntHelper<N, FindMe, Z<>> : std::integral_constant<int, -1> {}; // Not found.

template <int N, int FindMe, template <int...> class Z, int First, int... Rest>
struct FindIndexOfIntHelper<N, FindMe, Z<First, Rest...>> : FindIndexOfIntHelper<N+1, FindMe, Z<Rest...>> {};

template <int FindMe, typename Pack>
using FindIndexOfInt = FindIndexOfIntHelper<0, FindMe, Pack>;

template <typename, typename, typename, typename> struct PermutePackHelper;

template <typename Pack, template <typename...> class P, typename... Accumulated, typename IndicesPack, template <int...> class Z>
struct PermutePackHelper<Pack, P<Accumulated...>, IndicesPack, Z<>> {
using type = P<Accumulated...>;
};

template <typename Pack, template <typename...> class P, typename... Accumulated, typename IndicesPack, template <int...> class Z, int I, int... Is>
struct PermutePackHelper<Pack, P<Accumulated...>, IndicesPack, Z<I, Is...>> :
PermutePackHelper<Pack, P<Accumulated..., typename NthType<FindIndexOfInt<I, IndicesPack>::value, Pack>::type>,
IndicesPack, Z<Is...>> {};

template <typename, typename, typename> struct PermutePack;

template <template <typename...> class P, typename... Types, template <int...> class Z, int... Is, int... Js>
struct PermutePack<P<Types...>, Z<Is...>, Z<Js...>> : PermutePackHelper<P<Types...>, P<>, Z<Is...>, Z<Js...>> {};

最佳答案

有一种使用 boost::mpl 的方法,我认为它更容易理解(?)我添加了很多注释来解释这些步骤,并适当缩进到使代码更清晰一些...可能会有所帮助...

#include <iostream>
#include <type_traits>

#include <boost/mpl/vector_c.hpp>
#include <boost/mpl/sort.hpp>
#include <boost/mpl/comparison.hpp>
#include <boost/mpl/assert.hpp>
#include <boost/mpl/equal.hpp>
#include <boost/mpl/next_prior.hpp>
#include <boost/mpl/insert.hpp>
#include <boost/mpl/deref.hpp>
#include <boost/mpl/advance.hpp>
#include <boost/mpl/pair.hpp>
#include <boost/mpl/size.hpp>
#include <boost/mpl/transform.hpp>

using namespace boost::mpl;

template <typename R, typename It, typename End>
struct type_inserter
{
// index to insert
typedef typename deref<It>::type::first KType;
// type to insert
typedef typename deref<It>::type::second VType;
// recurse
typedef typename type_inserter<
typename insert<
R,
// calculate the location based on the index
typename advance<typename begin<R>::type, KType>::type,
VType
>::type,
typename next<It>::type,
End
>::type type;
};

template <typename R, typename End>
struct type_inserter<R, End, End>
{
typedef R type;
};

template <typename P>
struct index_access
{
typedef typename P::first type;
};

struct make_pair
{
template<typename Kv, typename Pv>
struct apply
{
typedef pair<Kv, Pv> type;
};
};

template <typename P1, typename P2, int ...I>
struct insert_pack
{
// transform P2 and indexes
static_assert(sizeof...(I) == size<P2>::value, "indexes/count P2 mismatch");
// this iterates through both sequences, constructing a pair and inserting into a vector
typedef typename transform<vector_c<int, I...>, P2, make_pair, back_inserter<vector0<>>>::type entries;
// sort the sequence by the index..
typedef typename sort<entries, greater<index_access<_1>, index_access<_2>>>::type reversed;
// once sorted, insert the sorted range into the main vector using custom inserter
typedef typename type_inserter<P1, typename begin<reversed>::type, typename end<reversed>::type>::type type;
};

int main()
{
typedef vector<int, double, char, long, int> pack1;
typedef vector<short, float, std::string> pack2;
// this combines the pack
typedef insert_pack<pack1, pack2, 2, 4, 1>::type combined;
// this is what we expect
typedef vector<int, std::string, double, short, char, long, float, int> packs;
// sanity check
BOOST_MPL_ASSERT(( equal< packs, combined> ));
}

关于c++ - 将任意数量的类型插入到一组模板参数中,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/28765858/

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