python - 在 Python 中创建列表对象类

Question

这是一个基本问题。我正在尝试以下代码:

class SMS_store:

def __init__(self):
    self=[]    #probably something is wrong here

def add_new_arrival(self,from_number,time_arrived,text_of_SMS):
    self.append([False,from_number,time_arrived,text_of_SMS])    #append list to self list
    self[len(self)-1]=tuple(self[len(self)-1])

def message_count(self):
    return len(self)

my_inbox=SMS_store()
my_inbox.add_new_arrival('01234','9:37 AM','How are you?')

但是我得到以下错误:

>>> 
Traceback (most recent call last):
  File "C:\Users\Arnob\Desktop\New Text Document.py", line 15, in <module>
    my_inbox.add_new_arrival('01234','9:37 AM','How are you?')
  File "C:\Users\Arnob\Desktop\New Text Document.py", line 8, in add_new_arrival
    self.append([False,from_number,time_arrived,text_of_SMS])    #append list to self list
AttributeError: 'SMS_store' object has no attribute 'append'
>>>

我的代码有什么问题？

Answer 1

你可以像这样继承list

class SMS_store(list):

    def add_new_arrival(self, from_number, time_arrived, text_of_SMS):
        self.append((False, from_number, time_arrived, text_of_SMS))    #append tuple to self

    def message_count(self):
        return len(self)

请注意，除非您想在那里做一些额外的事情，否则不需要 __init__。

你不需要 append 一个列表然后把它变成一个元组，你可以直接用()而不是[]来创建元组