python - 'LazySettings' 类型的 django 参数不可迭代；那么如何检查设置是否存在？

Question

from django.conf import settings

def my_view(self, request, *args, **kwargs):
    if 'LOCAL' in settings and settings.LOCAL:
        # do something

TypeError at ... argument of type 'LazySettings' is not iterable

然后如何检查设置是否存在？否则我会得到一个属性错误。

Answer 1

您可以使用 hasattr功能:

if hasattr(settings, 'name_of_setting'):
    # the setting exists
else:
    # the setting does not exist