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c# - Web 表单中的 Treeview 在父节点检查上检查子节点

转载 作者:太空狗 更新时间:2023-10-29 21:24:17 26 4
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我使用 System.Web.UI 类的 Treeview 控件来显示项目的类别和子类别。

我试过下面的代码,但没有希望

        protected void tvwOrganisation_TreeNodeCheckChanged(object sender, TreeNodeEventArgs e)
{
if (tvwOrganisation.CheckedNodes.Count > 0)
{
// the selected nodes.
foreach (TreeNode node in tvwOrganisation.CheckedNodes)
{

if (node.ChildNodes.Count > 0)
{
foreach (TreeNode childNode in node.ChildNodes)
{
childNode.Checked = true;
}
}

}

}
}

有什么方法可以做到这一点,我也尝试过 javascript。

还有什么是 AfterCheck 的替代品 - Web 表单中的 windows formd 事件。

最佳答案

树标签如下,

 <asp:TreeView ID="tvwRegionCountry" runat="server" ShowCheckBoxes="All" ExpandDepth="0"   AfterClientCheck="CheckChildNodes();" PopulateNodesFromClient="true" ShowLines="true" ShowExpandCollapse="true" OnTreeNodeCheckChanged="tvwRegionCountry_TreeNodeCheckChanged"
onclick="OnTreeClick(event)">
</asp:TreeView>

添加了以下 JS,如 asp.net treeview checkbox selection 中所述

<script language="javascript" type="text/javascript">
function OnTreeClick(evt) {
var src = window.event != window.undefined ? window.event.srcElement : evt.target;
var isChkBoxClick = (src.tagName.toLowerCase() == "input" && src.type == "checkbox");
if (isChkBoxClick) {
var parentTable = GetParentByTagName("table", src);
var nxtSibling = parentTable.nextSibling;
if (nxtSibling && nxtSibling.nodeType == 1)//check if nxt sibling is not null & is an element node
{
if (nxtSibling.tagName.toLowerCase() == "div") //if node has children
{
//check or uncheck children at all levels
CheckUncheckChildren(parentTable.nextSibling, src.checked);
}
}
//check or uncheck parents at all levels
CheckUncheckParents(src, src.checked);
}
}

function CheckUncheckChildren(childContainer, check) {
var childChkBoxes = childContainer.getElementsByTagName("input");
var childChkBoxCount = childChkBoxes.length;
for (var i = 0; i < childChkBoxCount; i++) {
childChkBoxes[i].checked = check;
}
}

function CheckUncheckParents(srcChild, check) {
var parentDiv = GetParentByTagName("div", srcChild);
var parentNodeTable = parentDiv.previousSibling;

if (parentNodeTable) {
var checkUncheckSwitch;

if (check) //checkbox checked
{
var isAllSiblingsChecked = AreAllSiblingsChecked(srcChild);
if (isAllSiblingsChecked)
checkUncheckSwitch = true;
else
return; //do not need to check parent if any(one or more) child not checked
}
else //checkbox unchecked
{
checkUncheckSwitch = false;
}

var inpElemsInParentTable = parentNodeTable.getElementsByTagName("input");
if (inpElemsInParentTable.length > 0) {
var parentNodeChkBox = inpElemsInParentTable[0];
parentNodeChkBox.checked = checkUncheckSwitch;
//do the same recursively
CheckUncheckParents(parentNodeChkBox, checkUncheckSwitch);
}
}
}

function AreAllSiblingsChecked(chkBox) {
var parentDiv = GetParentByTagName("div", chkBox);
var childCount = parentDiv.childNodes.length;
for (var i = 0; i < childCount; i++) {
if (parentDiv.childNodes[i].nodeType == 1) //check if the child node is an element node
{
if (parentDiv.childNodes[i].tagName.toLowerCase() == "table") {
var prevChkBox = parentDiv.childNodes[i].getElementsByTagName("input")[0];
//if any of sibling nodes are not checked, return false
if (!prevChkBox.checked) {
return false;
}
}
}
}
return true;
}

//utility function to get the container of an element by tagname
function GetParentByTagName(parentTagName, childElementObj) {
var parent = childElementObj.parentNode;
while (parent.tagName.toLowerCase() != parentTagName.toLowerCase()) {
parent = parent.parentNode;
}
return parent;
}

</script>

成功了...

关于c# - Web 表单中的 Treeview 在父节点检查上检查子节点,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/7157869/

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