gpt4 book ai didi

c# - 在 Listbox.ItemTemplate (WPF C#) 中查找控件

转载 作者:太空狗 更新时间:2023-10-29 21:07:22 24 4
gpt4 key购买 nike

我在 StackPanel 中找到正确的 TextBlock 控件时遇到了一些问题。我的标记:

<ListBox Name="lstTimeline" ItemContainerStyle="{StaticResource TwItemStyle}"
MouseDoubleClick="lstTimeline_MouseDoubleClick">
<ListBox.ItemTemplate>
<DataTemplate>
<DockPanel MaxWidth="{Binding ElementName=lstTimeline, Path=ActualWidth}">
<Border Margin="10" DockPanel.Dock="Left" BorderBrush="White"
BorderThickness="1" Height="48" Width="48" HorizontalAlignment="Center">
<Image Source="{Binding ThumbNail, IsAsync=True}" Height="48" Width="48" />
</Border>
<StackPanel Name="stkPanel" Margin="10" DockPanel.Dock="Right">
<TextBlock Text="{Binding UserName}" FontWeight="Bold" FontSize="18" />
<TextBlock Text="{Binding Text}" Margin="0,4,0,0" FontSize="14"
Foreground="#c6de96" TextWrapping="WrapWithOverflow" />
<TextBlock Text="{Binding ApproximateTime}" FontSize="14"
FontFamily="Georgia" FontStyle="Italic" Foreground="#BBB" />
<TextBlock Text="{Binding ScreenName}" Name="lblScreenName" FontSize="14"
FontFamily="Georgia" FontStyle="Italic" Foreground="#BBB"
Loaded="lblScreenName_Loaded" />
</StackPanel>
</DockPanel>
</DataTemplate>
</ListBox.ItemTemplate>
</ListBox>

我的双击代码:

private void lstTimeline_MouseDoubleClick(object sender, MouseButtonEventArgs e)
{
ListBoxItem lbi = (lstTimeline.SelectedItem as ListBoxItem);

StackPanel item = lbi.FindName("stkPanel") as StackPanel;
if (item != null)
MessageBox.Show("StackPanel null");
TextBlock textBox = item.FindName("lblScreenName") as TextBlock;
if (textBox != null)
MessageBox.Show("TextBlock null");

MessageBox.Show(textBox.Text);
}

但是 StackPanel 是空的。如何在 SelectedItem 中找到正确的 TextBlock

感谢您的帮助。

最佳答案

ListBoxItem myListBoxItem = (ListBoxItem)(lstUniqueIds.ItemContainerGenerator.ContainerFromIndex(lstUniqueIds.SelectedIndex));
ContentPresenter myContentPresenter = FindVisualChild<ContentPresenter>(myListBoxItem);
DataTemplate myDataTemplate = myContentPresenter.ContentTemplate;
CheckBox target = (CheckBox)myDataTemplate.FindName("chkUniqueId", myContentPresenter);
if (target.IsChecked)
{
target.IsChecked = false;
}
else
{
target.IsChecked = true;
}

函数 FindVisualChild 可以在 MSDN 页面上找到 FrameworkTemplate.FindName Method :

private childItem FindVisualChild<childItem>(DependencyObject obj)
where childItem : DependencyObject
{
for (int i = 0; i < VisualTreeHelper.GetChildrenCount(obj); i++)
{
DependencyObject child = VisualTreeHelper.GetChild(obj, i);
if (child != null && child is childItem)
return (childItem)child;
else
{
childItem childOfChild = FindVisualChild<childItem>(child);
if (childOfChild != null)
return childOfChild;
}
}
return null;
}

关于c# - 在 Listbox.ItemTemplate (WPF C#) 中查找控件,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/1800101/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com