python - 捕获套接字超时异常

Question

我想捕获套接字超时(最好是在异常中)... except urllib.error.URLError: 可以捕获它，但我需要区分死链接和超时。 ... 如果我取出 except urllib.error.URLError: 套接字超时不会捕获并且脚本会因 socket.timeout 错误而终止

import urllib.request,urllib.parse,urllib.error
import socket
import http
socket.setdefaulttimeout(0.1)


try:
    file2 = urllib.request.Request('http://uk.geforce.com/html://')
    file2.add_header("User-Agent","Mozilla/5.0 (Windows; U; Windows NT 6.0; en-US) AppleWebKit/525.13 (KHTML, like Gecko) Chrome/0.2.149.29 Safari/525.13")
    file3 = urllib.request.urlopen(file2).read().decode("utf8", 'ignore')
except urllib.error.URLError: print('fail')
except socket.error: print('fail')
except socket.timeout: print('fail')
except UnicodeEncodeError: print('fail')
except http.client.BadStatusLine: print('fail')
except http.client.IncompleteRead: print('fail')
except urllib.error.HTTPError: print('fail')

print('done')

Answer 1

...
except urllib.error.URLError, e:
    print type(e.reason)

你会看到 <class 'socket.timeout'>每当有套接字超时时。这是你想要的吗？

例如:

try:
  data = urllib2.urlopen("http://www.abcnonexistingurlxyz.com")
except Exception,e:
  print type(e.reason)
... 
<class 'socket.timeout'>