c++ - 执行类的成员函数

Question

我正在尝试以一种方式试验 C++11 线程，它接受一个类的成员函数作为线程构造函数的参数，如下面第 20 行标记的第一个代码片段所示。类定义在第二个代码片段中给出。编译这段代码时，我收到了第三个片段中显示的一堆错误。谁能告诉我我做错了什么？谢谢。

片段 1:线程初始化(main_app.cpp)

#include <thread>
#include "ServiceRegistrar.hpp"

#define SERVER_TYPE  100065
#define SERVER_INST_LOWER  1
#define SERVER_INST_UPPER  2
#define TIMEOUT  500000

int main()
{
  ServiceRegistrar sr1(SERVER_TYPE, TIMEOUT, SERVER_INST_LOWER, SERVER_INST_LOWER);
      /*LINE 20 is the following*/
  std::thread t(&ServiceRegistrar::subscribe2TopologyServer, sr1);
t.join();
  sr1.publishForSRs();

}

片段 2:类定义

class ServiceRegistrar
{
  public:
    ServiceRegistrar(int serverType, int serverTimeOut, int serverInstanceLower, int serverInstanceUpper)
       : mServerType(serverType),
         mServerTimeOut(serverTimeOut),
         mServerInstanceLower(serverInstanceLower),
         mServerInstanceUpper(serverInstanceUpper)
         { }

     void subscribe2TopologyServer();
     void publishForSRs();
     void publishForServices();

  private:
     int mServerType;
     int mServerTimeOut;
     int mServerInstanceLower;
         int mServerInstanceUpper;           
  };

SNIPPET 3:编译输出

  $ g++ -g -c -Wall -std=c++11 main_app.cpp -pthread
  In file included from /usr/include/c++/4.7/ratio:38:0,
             from /usr/include/c++/4.7/chrono:38,
             from /usr/include/c++/4.7/thread:38,
             from main_app.cpp:8:
  /usr/include/c++/4.7/type_traits: In instantiation of ‘struct    std::_Result_of_impl<false, false, std::_Mem_fn<void (ServiceRegistrar::*)()>,    ServiceRegistrar>’:
  /usr/include/c++/4.7/type_traits:1857:12:   required from ‘class std::result_of<std::_Mem_fn<void (ServiceRegistrar::*)()>(ServiceRegistrar)>’
  /usr/include/c++/4.7/functional:1563:61:   required from ‘struct std::_Bind_simple<std::_Mem_fn<void (ServiceRegistrar::*)()>(ServiceRegistrar)>’
 /usr/include/c++/4.7/thread:133:9:   required from ‘std::thread::thread(_Callable&&,  _Args&& ...) [with _Callable = void (ServiceRegistrar::*)(); _Args = {ServiceRegistrar&}]’
 main_app.cpp:20:64:   required from here
/usr/include/c++/4.7/type_traits:1834:9: error: no match for call to     ‘ (std::_Mem_fn<void (ServiceRegistrar::*)()>) (ServiceRegistrar)’

Answer 1

显然这是一个 gcc 4.7 bug ...使用

std::thread t(&ServiceRegistrar::subscribe2TopologyServer, &sr1);

相反。

编辑:实际上，您可能不想将 sr1 复制到 t 的线程本地存储中，所以这样更好。