c++ - 可乐机代码的 switch 语句

Question

我一直使用 if else 语句而不是 switch 语句，但我决定尝试一个 switch out。我用一个开关做了基本的可乐机程序，但我终究无法弄清楚为什么它不能正常工作。当我使用数字 1-5 作为输入时，它会继续给出开关默认错误消息，而不是 case cout 语句(例如“您选择了可口可乐”)。显然一定是我没有看到的错误/

#include <iostream>

using namespace std;

int main()
{
    int number;

    cout << "Beverage List" << endl;
    cout << "Coke = 1" << endl;
    cout << "Dr. Pepper = 2" << endl;
    cout << "Water = 3" << endl;
    cout << "Sprite = 4" << endl;
    cout << "Lemonade = 5" << endl << endl << endl;
    cout << "Enter a number to choose a beverage: ";
    cin >> number;

    switch (number)
    {
    case '1':
        cout << "You chose Coke";
        break;

    case '2':
        cout << "You chose Dr. Pepper";
        break;

    case '3':
        cout << "You chose Water";
        break;

    case '4':
        cout << "You chose Sprite";
        break;

    case '5':
        cout << "You chose Lemonade";
        break;

    default:
        cout << "Error: Choice was not valid. Here is your money back.";

    }

    cout << "\n";
    system("pause");
    return 0;
}

Answer 1

字符 '1' 与数字 1 不同。

改变

case '1':

到

case 1: