python - 给定它的值，更改所选 matplotlib 直方图 bin 条的颜色

Question

Similar to a question I asked previously ，我有一个像这样的 MWE:

import pandas as pd
import matplotlib.pyplot as plt
import seaborn as sns
import numpy as np

pd.Series(np.random.normal(0, 100, 1000)).plot(kind='hist', bins=50, color='orange')

bar_value_to_colour = 102

然后我想使用 bar_value_to_colour 变量自动将值所在的直方图上的条形颜色更改为蓝色，例如:

我怎样才能做到这一点？

Answer 1

使用 rectangle.get_x() 很容易获得柱的 x 坐标，但问题是柱没有精确地绘制在特定值处，所以我不得不选择最接近的。这是我的解决方案:

import pandas as pd
import matplotlib.pyplot as plt
import numpy as np

s = pd.Series(np.random.normal(0, 100, 10000))
p = s.plot(kind='hist', bins=50, color='orange')

bar_value_to_label = 100
min_distance = float("inf")  # initialize min_distance with infinity
index_of_bar_to_label = 0
for i, rectangle in enumerate(p.patches):  # iterate over every bar
    tmp = abs(  # tmp = distance from middle of the bar to bar_value_to_label
        (rectangle.get_x() +
            (rectangle.get_width() * (1 / 2))) - bar_value_to_label)
    if tmp < min_distance:  # we are searching for the bar with x cordinate
                            # closest to bar_value_to_label
        min_distance = tmp
        index_of_bar_to_label = i
p.patches[index_of_bar_to_label].set_color('b')

plt.show()

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