c++ - 如何解决除以零 C++

Question

我对编程很陌生，因为我必须上一门课才开始。

在实验室中，我们必须编写一个简单的计算器(加法、减法、除法和乘法)，然后插入老师给我们的集合数字。当然，其中两组数字中有零。您如何将其编码为未定义而不是浮点异常(核心已转储)

#include <iostream>
#include <cmath>

using namespace std;

int main() {

    int a;
    int b;
    float c;
    float d;
    float e;
    float f;
    float g;
    float h;
    float i;
    float j;

    cout << "Enter value for a\n";
    cout << "Enter value for b\n";
    cout << "Then press return.\n";

    cin >> a;
    cin >> b;

    c = a + b;
    d = a - b;
    e = a * b;
    f = a / b;

    g = sqrt (c);
    h = sqrt (d);
    i = sqrt (e);
    j = sqrt (f);

    cout << a << " value for a\n";
    cout << b << " value for b\n";
    cout << "value for c is " << c << " \n";
    cout << "value for d is " << d << " \n";
    cout << "value for e is " << e << " \n";
    cout << "value for f is " << f << " \n";
    cout << "value for g is " << g << " \n";
    cout << "value for h is " << h << " \n";
    cout << "value for i is " << i << " \n";
    cout << "value for j is " << j << " \n";

    return 0;
}

Answer 1

也许更好的方法是清理您的输入。 “如果用户为 b 输入 0，则说未定义，否则，尝试计算。”

你还会遇到这个问题，如果 a 小于 b，sqrt() 函数将抛出也是一个错误(并非设计用于处理负输入)。