gpt4 book ai didi

c# - 从现有实例创建 IList 的新实例并修改它

转载 作者:太空狗 更新时间:2023-10-29 20:54:53 25 4
gpt4 key购买 nike

<分区>

给定以下代码:

public class Item
{
private int _id;
private int _order;
private string _name;

public int Id
{
get { return _id; }
set { _id = value; }
}

public int Order
{
get { return _order; }
set { _order = value; }
}

public string Name
{
get { return _name; }
set { _name = value; }
}

public static IList<Item> InitList1()
{
var list = new List<Item>
{
new Item { Id = 1, Order = 1, Name = "Alpha" },
new Item { Id = 2, Order = 2, Name = "Bravo" },
new Item { Id = 3, Order = 3, Name = "Charlie" },
new Item { Id = 4, Order = 4, Name = "Delta" }
};

return list;
}
}

class Program
{
static void Main(string[] args)
{
// Initialize the lists
IList<Item> list1 = Item.InitList1();
IList<Item> list2 = list1.ToList();
IList<Item> list3 = new List<Item>(list1);

// Modify list2
foreach (Item item in list2)
item.Order++;

// Modify list3
foreach (Item item in list3)
item.Order++;

// Output the lists
Console.WriteLine(string.Format("\nList1\n====================="));
foreach (Item item in list1)
Console.WriteLine(string.Format("Item - id: {0} order: {1} name: {2}", item.Id, item.Order, item.Name));

Console.WriteLine(string.Format("\nList2\n====================="));
foreach (Item item in list2)
Console.WriteLine(string.Format("Item - id: {0} order: {1} name: {2}", item.Id, item.Order, item.Name));

Console.WriteLine(string.Format("\nList3\n====================="));
foreach (Item item in list3)
Console.WriteLine(string.Format("Item - id: {0} order: {1} name: {2}", item.Id, item.Order, item.Name));

Console.Write("\nAny key to exit...");
Console.ReadKey();
}
}

输出将是:

List1
=====================
Item - id: 1 order: 3 name: Alpha
Item - id: 2 order: 4 name: Bravo
Item - id: 3 order: 5 name: Charlie
Item - id: 4 order: 6 name: Delta


List2
=====================
Item - id: 1 order: 3 name: Alpha
Item - id: 2 order: 4 name: Bravo
Item - id: 3 order: 5 name: Charlie
Item - id: 4 order: 6 name: Delta

List3
=====================
Item - id: 1 order: 3 name: Alpha
Item - id: 2 order: 4 name: Bravo
Item - id: 3 order: 5 name: Charlie
Item - id: 4 order: 6 name: Delta

Any key to exit...

谁能给我解释一下:

  1. 为什么在创建新列表(list2 和 list3)后,对这些列表的操作会影响 list1(以及随后的其他两个列表)?和

  2. 如何在不影响 list1 的情况下创建 list1 的新实例并对其进行修改?

25 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com