c++ - 如何将字符串添加到 char 元素的二维数组中？

Question

我有以下用 C++ 编写的程序:

#include <iostream>

using namespace std;

int main()

{
    int age[5];
    char name[5][10];

    age[0]=10;
    age[1]=20;
    age[2]=30;
    age[3]=25;
    age[4]=40;

    name[0]="abc";
    name[1]="abc";
    name[2]="abc";
    name[3]="abc";
    name[4]="abc";

    cout<<name[0]<<" is "<<age[0]<<"years old";
    cout<<"\n";
    cout<<name[1]<<" is "<<age[1]<<"years old";
    cout<<"\n";
    cout<<name[2]<<" is "<<age[2]<<"years old";
    cout<<"\n";
    cout<<name[3]<<" is "<<age[3]<<"years old";
    cout<<"\n";
    cout<<name[4]<<" is "<<age[4]<<"years old";
    cout<<"\n\n";

    system("PAUSE");

}

当我编译并运行它时，出现以下错误:

error C2440: '=' : cannot convert from 'const char [3]' to 'char [10]' There is no context in which this conversion is possible

error C2440: '=' : cannot convert from 'const char [2]' to 'char [10]' There is no context in which this conversion is possible

error C2440: '=' : cannot convert from 'const char [2]' to 'char [10]' There is no context in which this conversion is possible

error C2440: '=' : cannot convert from 'const char [2]' to 'char [10]' There is no context in which this conversion is possible

error C2440: '=' : cannot convert from 'const char [2]' to 'char [10]' There is no context in which this conversion is possible

我在 Windows 7 下运行 MSVC 2008。我尝试了很多可能的解决方案，但未能解决这个问题。任何帮助将不胜感激，

Answer 1

您正在处理 name 数组，就好像它是这样定义的:

char *name[5];

因此要么以这种方式定义它，要么使用以下代码来填充它:

strcpy(name[0], "abc");
strcpy(name[1], "abc");
strcpy(name[2], "abc");
strcpy(name[3], "abc");
strcpy(name[4], "abc");

我更喜欢前一种选择。关键是您正在尝试将 char * 分配给 char [] ，这就是 strcpy 的用途。鉴于您在这种情况下无论如何都在操作初始化的 C 字符串，您最好在整个代码中处理 char *。