python - xlrd 单元格的原始值

Question

我正在使用 xlrd 读取 xls 文件。问题是，当 xlrd 读取这样的值时 "12/09/2012"，我得到这样的结果 "xldate:41252.0"。当我使用 xlrd.xldate_as_tuple 时，我得到了这个结果:

(2016, 12, 10, 0, 0, 0)

我的代码:

curr_row = -1
while curr_row < num_rows:
    curr_row += 1
    row = worksheet.row(curr_row)     
        for x in xrange(num_cols):
            field_type = worksheet.cell_type(curr_row, x)
            if field_type == 3: # this is date
                field_value = worksheet.cell_value(curr_row, x)
                print worksheet.cell(curr_row, x).value
                print xlrd.xldate_as_tuple(field_value, 1)

结果:

41252.0
(2016, 12, 10, 0, 0, 0)

这两个结果对我来说都是错误的。如何使用 xlrd 获取原始单元格值“12/09/2012”？

Answer 1

根据docstring ，您应该将工作簿的日期模式作为第二个参数传递给 xldate_as_tuple:

from datetime import datetime
import xlrd


book = xlrd.open_workbook("test.xls")
sheet = book.sheet_by_index(0)
a1 = sheet.cell_value(rowx=0, colx=0)

print a1  # prints 41252.0
print xlrd.xldate_as_tuple(a1, 1)  # prints (2016, 12, 10, 0, 0, 0)

a1_tuple = xlrd.xldate_as_tuple(a1, book.datemode)  
print a1_tuple  # prints (2012, 12, 9, 0, 0, 0)

a1_datetime = datetime(*a1_tuple)
print a1_datetime.strftime("%m/%d/%Y")  # prints 12/09/2012