gpt4 book ai didi

python - 获取二维 numpy 数组中大于阈值的元素的索引

转载 作者:太空狗 更新时间:2023-10-29 20:41:32 24 4
gpt4 key购买 nike

我有一个 2D numpy 数组:

x = [[  1.92043482e-04   0.00000000e+00   0.00000000e+00   0.00000000e+00
0.00000000e+00 0.00000000e+00 2.41005634e-03 0.00000000e+00
7.19330120e-04 0.00000000e+00 0.00000000e+00 1.42886875e-04
0.00000000e+00 0.00000000e+00 0.00000000e+00 0.00000000e+00
0.00000000e+00 9.79279411e-05 7.88888657e-04 0.00000000e+00
0.00000000e+00 1.40425916e-01 0.00000000e+00 1.13955893e-02
7.36868947e-03 3.67091988e-04 0.00000000e+00 0.00000000e+00
0.00000000e+00 0.00000000e+00 1.72037105e-03 1.72377961e-03
0.00000000e+00 0.00000000e+00 1.19532061e-01 0.00000000e+00
0.00000000e+00 0.00000000e+00 0.00000000e+00 3.37249481e-04
0.00000000e+00 0.00000000e+00 0.00000000e+00 0.00000000e+00
0.00000000e+00 0.00000000e+00 1.75111492e-03 0.00000000e+00
0.00000000e+00 1.12639313e-02]
[ 0.00000000e+00 0.00000000e+00 1.10271735e-04 5.98736562e-04
6.77961628e-04 7.49569659e-04 0.00000000e+00 0.00000000e+00
2.91697850e-03 0.00000000e+00 0.00000000e+00 0.00000000e+00
0.00000000e+00 0.00000000e+00 3.30257021e-04 2.46629275e-04
0.00000000e+00 1.87586441e-02 6.49103144e-04 0.00000000e+00
1.19046355e-04 0.00000000e+00 0.00000000e+00 2.69499898e-03
1.48525386e-02 0.00000000e+00 0.00000000e+00 0.00000000e+00
0.00000000e+00 0.00000000e+00 0.00000000e+00 1.18803119e-03
3.93100829e-04 0.00000000e+00 3.76245304e-04 2.79537738e-02
0.00000000e+00 1.20738457e-03 9.74669064e-06 7.18680093e-04
1.61546793e-02 3.49360861e-04 0.00000000e+00 0.00000000e+00
0.00000000e+00 0.00000000e+00 0.00000000e+00 0.00000000e+00
0.00000000e+00 0.00000000e+00]]

如何获取大于 0.01 的元素的索引?

现在,我正在执行 t = np.argmax(x, axis=1) 以获取每个最大值的索引,其结果是:[ 21 35]。我如何实现上述目标?

最佳答案

您可以使用 np.argwhere 返回数组中与 bool 条件匹配的所有条目的索引:

>>> x = np.array([[0,0.2,0.5],[0.05,0.01,0]])

>>> np.argwhere(x > 0.01)
array([[0, 1],
[0, 2],
[1, 0]])

关于python - 获取二维 numpy 数组中大于阈值的元素的索引,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/44296310/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com