c++ - 通过减少 if 语句使代码更高效

Question

我正在制作一个食谱分配器程序，它将根据以下内容打印食谱:

• 食物的辣度
• 做饭需要的时间

以后我可能会添加更多内容。

#include <iostream>
#include <string>
using namespace std;

int main()
{
    string input = "";
    string recipe1 = "A mild recipe that takes 10 mins";
    string recipe2 = "A mild recipe that takes 20 mins";
    string recipe3 = "A medium recipe that takes 10 mins";
    string recipe4 = "a mild recipe that takes 20 mins";

    cout << "Hello to the recipe dispenser 2000" << endl << "I will now begin with some questions to get the perfect recipe for you" << endl << "Do you like your food mild, medium, or hot?" << endl;
    getline (cin, input);
    if(input == "mild")
      cout << "Would you like a recipe that takes 10 or 20 mins?" << endl;
      getline (cin, input);
      if(input == "10" or input == "10 mins")
        cout << recipe1 << endl;
}

但是我现在的代码看起来效率很低，因为我必须写出总共 6 个 if 语句才能完成代码。

有什么办法可以缩短吗？
例如给每个食谱添加一些标签什么的，比如[10, mild] 到recipe1，然后代码会根据标签输出响应。

任何想法都会受到赞赏。

Answer 1

int main()
{
    string input = "";
    int inp;
    map< string,map<int,string> > recipe;
    recipe["mild"][10]="A mild recipe that takes 10 mins";
    recipe["mild"][20]= "A mild recipe that takes 20 mins";
    recipe["medium"][10]= "A medium recipe that takes 10 mins";

    cout << "Hello to the recipe dispenser 2000" << endl << "I will now begin with some questions to get the perfect recipe for you" << endl << "Do you like your food mild, medium, or hot?" << endl;
    getline (cin, input);
    cout << "Would you like a recipe that takes 10 or 20 mins?" << endl;
    cin>>inp;
    try
    {
        cout<<(recipe.at(input)).at(inp);
    }
    catch(exception &e)
    {
        cerr<<input<<" , "<<inp<<" has not been invented yet!\n";
    }
    return 0;
}

在我看来，STL 的使用非常优雅。希望这对您有用。
引用

• 对于 map :http://www.cplusplus.com/reference/map/
• 和http://www.cprogramming.com/tutorial/stl/stlmap.html
• try catch :http://www.cplusplus.com/doc/tutorial/exceptions/