c++ - C++ 中的复合类型、const 和 auto

Question

我正在尝试理解这段代码。我一直想弄清楚为什么 d 和 e 是 int* 和 const int*。我需要一些帮助。

const int ci = i, &cr = ci;
auto b = ci; // b is an int (top-level const in ci is dropped)
auto c = cr; // c is an int (cr is an alias for ci whose const is top-level)
auto d = &i; // d is an int*(& of an int object is int*)
auto e = &ci; // e is const int*(& of a const object is low-level const)

Answer 1

&i 的意思是“获取i的地址”。因为i是一个int，所以&i的类型是int*。由于 automatic type deduction rules，d 的类型被推断为 int* .

同样的推理也适用于 ci。唯一的区别是 const 限定符。