python - 如何将 python 时间戳字符串转换为纪元？

Question

我有以下字符串:

mytime = "2009-03-08T00:27:31.807Z"

如何在 python 中将其转换为纪元？

我试过:

import time
p = '%Y-%m-%dT%H:%M:%S'
int(time.mktime(time.strptime(s, p)))

但它不适用于 31.807Z。

Answer 1

分为两部分:

1. 将时间字符串转换为分割时间。参见 How to parse ISO formatted date in python?
2. Convert the UTC time to "seconds since the Epoch" (POSIX timestamp) .

#!/usr/bin/env python
from datetime import datetime

utc_time = datetime.strptime("2009-03-08T00:27:31.807Z", "%Y-%m-%dT%H:%M:%S.%fZ")
epoch_time = (utc_time - datetime(1970, 1, 1)).total_seconds()
# -> 1236472051.807

如果您确定要忽略几分之一秒并获得整数结果:

#!/usr/bin/env python
import time
from calendar import timegm

utc_time = time.strptime("2009-03-08T00:27:31.807Z", "%Y-%m-%dT%H:%M:%S.%fZ")
epoch_time = timegm(utc_time)
# -> 1236472051

要支持与闰秒相对应的时间戳，例如 Wed July 1 2:59:60 MSK 2015，您可以 use a combination of time.strptime() and datetime (if you care about leap seconds you should take into account the microseconds too) .