c# - 将模型从一个 Action 传递到同一 Controller 中的另一个 Action

Question

我试图将我的模型 List< Models.Statement > statementList 从一个 Action 传递到另一个 Action ，但我在第二个 Controller 中收到空值。请建议这里有什么问题。甚至尝试过:

return RedirectToAction("WriteInTemplate", new { statementList = statementList });

请帮忙。

    public ActionResult SendPdfStatement(string InvoiceNumber)
    {
        try
        {
            InvoiceNumber = InvoiceNumber.Trim();

            ObjectParameter[] parameters = new ObjectParameter[1];
            parameters[0] = new ObjectParameter("InvoiceNumber", InvoiceNumber);

            List<Models.Statement> statementList = new List<Models.Statement>();
            statementList = _db.ExecuteFunction<Models.Statement>("uspInvoiceStatement", parameters).ToList<Models.Statement>();

            //WriteInTemplate(statementList);
            return RedirectToAction("WriteInTemplate", statementList );

        }
        catch (Exception e)
        {
            InvoiceSearchTool.Models.udtExceptionTable exception = new udtExceptionTable();
            exception.MethodName = "SendPdfStatement";
            exception.Exception = e.ToString();
            exception.Date = DateTime.Now;
            DYNAMICS_EXTEntities db = new DYNAMICS_EXTEntities();
            db.AddToudtExceptionTables(exception);
            db.SaveChanges();  
            return View("Error");
        }
    }

    public ActionResult WriteInTemplate(List<Models.Statement> statementList)
    {
        try
        {
            string invoiceNumber = statementList.FirstOrDefault().Invoice.ToString().Trim();
        ...................snip..........


            return RedirectToAction("CreateMessageWithAttachment", "email", invoiceNumber); 
        }
        catch (Exception e)
        {
            InvoiceSearchTool.Models.udtExceptionTable exception = new udtExceptionTable();
            exception.MethodName = "WriteInTemplate";
            exception.Exception = e.ToString();
            exception.Date = DateTime.Now;
            DYNAMICS_EXTEntities db = new DYNAMICS_EXTEntities();
            db.AddToudtExceptionTables(exception);
            db.SaveChanges();

            return View("Error");
        }

    }

Answer 1

请看here to pass your Model

您没有传递“statementList”，而是传递了 new {statementList= statementList}，只需传递模型就可以了。

return RedirectToAction("WriteInTemplate", statementList);

sino 的回答