c++ - x86 Intel Assembly 和 C++ - 数组周围的堆栈已损坏

Question

错误:

Run-Time Check Failure #2 - Stack around the variable 'arr' was corrupted.

这似乎是这个论坛上的一个常见错误；但是，我找不到其中混入了汇编代码的程序。基本上，我的程序是将十进制转换为二进制(16 位表示)。完成编码后，一切似乎都可以正确计算，并且可以毫无问题地将十进制转换为二进制；但是，在 “按任意键继续......” 之后，会弹出上述错误。

我不认为是 C++ 代码导致了这个问题，因为它非常基础，而且只用于调用汇编函数。

同样，计算是正确的，因为程序将产生正确的转换(即:十进制 = 10，二进制转换:0000000000001010)，但只是在程序结束时给我错误。

C++代码:

#include <iostream>

using namespace std;

extern"C" void decToBin(char[], int, int);

int main()
{
//Initialize array and variables
const int SIZE = 16;
char arr[SIZE] = { NULL };
int dec = 0;

//Ask user for integer that they want to convert
cout << "Please enter integer you want to convert to binary: ";
cin >> dec;

//Assembly function to convert integer
decToBin(arr, dec, SIZE);

cout << "The 16-bit binary representation of " << dec << " is: ";

//Display the 16-bit binary conversion
for (int i = 0; i < SIZE; i++)
    cout << arr[i];

cout << endl;

system("PAUSE");
return 0;
}

汇编代码:

.686
.model flat

.code

_decToBin PROC              ;Start of project

start:
push ebp
mov ebp,esp             ;Stack pointer to ebp

mov eax,[ebp+8]         ;Address of first array element
mov cx,[ebp+12]         ;Integer number being passed - Copying onto 16 bit register
mov edx,[ebp+16]        ;Size of array

loopme:                     ;Loop to fill in array
mov ebx,0               ;Initializes ebx to store carry flag after shift
cmp edx,0               ;Compare edx with 0 to see if we should continue
je alldone              

shl cx,1                ;Shift the value to the left
adc ebx,0               ;Check carry flag and add 1 if CF(CY) is set to 1 and stay at 0 if CF(CY) is 0
add ebx,48              ;Since array is CHAR, adding 48 will give correct 0 or 1 instead of null

mov [eax],ebx           ;Copy the 0's or 1's into the array location

dec edx                 ;Decrement the counter
inc eax                 ;Move the array up an index

jmp loopme

alldone:    
pop ebp
ret

_decToBin ENDP

END

Answer 1

我没有汇编程序来编译你的代码，但你在这一行将 32 位值写入 char[]:

mov [eax],ebx           ;Copy the 0's or 1's into the array location

因此，最后一次写入会将内存位置 arr[SIZE-1] 更新为 arr[SIZE+2]。