c++ - std::getline 不接受 std::back_insert_iterator

Question

int main() { 
    std::deque<std::string> mydeque;
    std::back_insert_iterator<decltype(mydeque)> myback_insert_iterator(mydeque);
    std::ifstream myifstream("test.txt");
    while(std::getline(myifstream, *myback_insert_iterator)) {
    }
}

我只是想将一个文本文件逐行读取到一个字符串容器中。这会产生编译器错误:

C2784: could not deduce template argument for 'std::basic_istream<_Elem,_Traits> &' from 'std::ifstream'

怎么了？

Answer 1

尝试:

int main()
{
    std::deque<std::string> mydeque;
    std::ifstream myifstream("test.txt");

    std::string line;
    while(std::getline(myifstream, line)
    {
        mydeque.push_back(line);
    }
}

如果每行一个词，你可以简化为:

int main()
{
    std::deque<std::string> mydeque;
    std::ifstream myifstream("test.txt");

    // Note: istream_iterator<T> uses std::istream& operator>>(std::istream&, T&) to
    //       read data from the stream. If `T` is a std::string this means it will
    //       read a single space separated word.

    std::copy(std::istream_iterator<std::string>(myifstream),
              std::istream_iterator<std::string>(),
              std::back_inserter(mydeque)
             );
}

如果每行包含多个单词并且您想使用后置插入器，那么您需要定义一个类来读取对象中的整行，该类可以与迭代器一起使用:

struct Line
{
    std::string data;
    operator std::string const&() const {return data;}

    friend std::istream& operator>>(std::istream& s, Line& dst)
    {
        return std::getline(s, dst.data);
    }
};

int main()
{
    std::deque<std::string> mydeque;
    std::ifstream myifstream("test.txt");

    std::copy(std::istream_iterator<Line>(myifstream),
              std::istream_iterator<Line>(),
              std::back_inserter(mydeque)
             );
}

或者我们可以只使用构造器:

int main()
{
    std::ifstream myifstream("test.txt");
    std::deque<std::string> mydeque(std::istream_iterator<Line>(myifstream),
                                    (std::istream_iterator<Line>()));
    // Note: Extra brace required around second iterator here
    //       This is to avoid the problem with the `Most Vexing Parse`
    //       Which would otherwise make this a function declaration

}