c++ - 派生类的成员函数是否继承了基类的虚拟性？

Question

假设我们有以下两个类，A 是具有虚析构函数的基类，B 是其析构函数没有'virtual' 限定符的派生类。我的问题是，如果我要从 B 派生更多的类，B 的析构函数是否会自动继承虚拟性，或者我需要明确地将 'virtual' 放在 '~B() {... }'

class A
{
public:
    A() { std::cout << "create A" << std::endl;};
    virtual ~A() { std::cout << "destroy A" << std::endl;};
};

class B: A
{
public:
    B() { std::cout << "create B" << std::endl;};
    ~B() { std::cout << "destroy B" << std::endl;};
};

Answer 1

来自 C++ 标准(第 10.3 节):

If a virtual member function vf is declared in a class Base and in a class Derived, derived directly or indirectly from Base, [...] then Derived::vf is also virtual (whether or not it is so declared).

是的。