c++ - 错误 : postfix ‘unaryOperators unaryOperators::operator++(const unaryOperators&)’ must take ‘int’ as its argument

Question

unaryOperators operator++ (const unaryOperators &one);
对于在类中声明的这个，我应该得到错误“参数太多”等，但我得到的错误是:

错误:后缀“unaryOperators unaryOperators::operator++(const unaryOperators&)”必须将“int”作为其参数

为什么必须将“int”作为参数？这是什么意思？

海湾合作委员会Linux

Answer 1

来自 here :

Since the prefix and postfix ++ operators can have two definitions, the C++ language gives us two different signatures. Both are called operator++(), but the prefix version takes no parameters and the postfix version takes a dummy int.