C++ 11 : Start thread with member function and this as parameter

Question

使用这段代码，我得到了错误:

错误 1 ​​error C2064: term does not evaluate to a function takeing 1 arguments c:\program files (x86)\microsoft visual studio 11.0\vc\include\functional 1152 1 Pipeline

class PipelineJob {
private:
    std::thread *thread;
    void execute(PipelineJob* object);
public:

    void execute(PipelineJob* object)
    {
    }

    PipelineJob()
    {
        this->thread = new std::thread(&PipelineJob::execute, this);
    }
};

我尝试了很多变体，现在有人如何解决这个问题？

Answer 1

为简单起见，删除了模板和指针，这或多或少是您想要的:

class PipelineJob 
{
private:
    std::thread thread_;
    void execute(PipelineJob* object) { ..... }
public:
    PipelineJob()
    {
      thread_ = std::thread(&PipelineJob::execute, this, this);
    }
    ~PipelineJob() { thread_.join(); }
};

请注意，this 被两次传递给 std::thread 构造函数:一次用于成员函数的隐式第一个参数，第二次用于可见参数 成员函数的 PipelineJob* 对象。

如果您的execute 成员函数不需要外部PipelineJob 指针，那么您将需要像

class PipelineJob 
{
private:
    std::thread thread_;
    void execute() { ..... }
public:
    PipelineJob()
    {
      thread_ = std::thread(&PipelineJob::execute, this);
    }
    ~PipelineJob() { thread_.join(); }
};