arrays - 根据内部数组条件查找数组中的项目

Question

如何在对象数组内部的数组中查找 id

例子:

let arrayobjects = [{ 
    id: 1, 
    name: "oinoin", 
    description: ["one", "two", "three"]
}, { 
    id: 2, 
    name: "zatata", 
    description: ["four", "five", "six"]
}];

如何找到单词“二”的id？

Answer 1

如果需要不止一项，可以通过Array#filter过滤数组，通过 Array#includes 检查每个项目的属性 description 是否包含单词 two (ES7)，然后使用 Array#map 映射结果以仅获取这些项目的 id .

let arrayobjects = [
      { id: 1, name: "oinoin", description: ["one", "two", "three"] }, 
      { id: 2, name: "zatata", description: ["four", "five", "six"] }
];

const ids = arrayobjects.filter(item => item.description.includes('two'))
                        .map(item => item.id);
                        
console.log(ids);

如果你只有一个项目，你可以只使用Array#find并做同样的检查

let arrayobjects = [
      { id: 1, name: "oinoin", description: ["one", "two", "three"] }, 
      { id: 2, name: "zatata", description: ["four", "five", "six"] }
];

const item = arrayobjects.find(item => item.description.includes('two'));
                        
console.log(item.id);