python - XOR Python 文本加密/解密

Question

我知道有一个可以在 Python 中导入的内置 xor 运算符。我正在尝试执行异或加密/解密。到目前为止，我有:

 def xor_attmpt():
    message = raw_input("Enter message to be ciphered: ")
    cipher = []
    for i in message:
        cipher.append(bin(ord(i))[2::])#add the conversion of the letters/characters
#in your message from ascii to binary withoout the 0b in the front to your ciphered message list
    cipher = "".join(cipher) 
    privvyKey = raw_input("Enter the private key: ")
    keydecrypt = []
    for j in privvyKey:
        keydecrypt.append(bin(ord(j))[2::]) #same
    keydecrypt = "".join(keydecrypt )#same

    print "key is '{0}'" .format(keydecrypt) #substitute values in string
    print "encrypted text is '{0}'" .format(cipher)
    from operator import xor
    for letter in message:
        print xor(bool(cipher), bool(keydecrypt))

这个:

>  for letter in message:
    print xor(bool(cipher), bool(keydecrypt))

是我的 python 开始出错的地方。

输出看起来像这样

    Enter message to be ciphered: hello
Enter the private key: \@154>
key is '10111001000000110001110101110100111110'
encrypted text is '11010001100101110110011011001101111'
False
False
False
False
False

我搞砸的是试图比较这两个二进制文件( key 和加密)并给出 true(1) 或 false(为 0)。然后 xor 应该通过比较两者给我一个结果 1 和 0 二进制列表。有什么意见吗？

Answer 1

这是来自 XOR Cipher Wikipedia article 的代码示例的变体:

def xor(data, key): 
    return bytearray(a^b for a, b in zip(*map(bytearray, [data, key]))) 

示例(Python 2):

>>> one_time_pad = 'shared secret' 
>>> plaintext = 'unencrypted' 
>>> ciphertext = xor(plaintext, one_time_pad) 
>>> ciphertext 
bytearray(b'\x06\x06\x04\x1c\x06\x16Y\x03\x11\x06\x16') 
>>> decrypted = xor(ciphertext, one_time_pad) 
>>> decrypted
bytearray(b'unencrypted')
>>> plaintext == str(decrypted)
True