python - SQLAlchemy 继承不起作用

Question

我正在使用 Flask 和 SQLAlchemy。我使用了自己的抽象基类和继承。当我尝试在 python shell 中使用我的模型时，出现以下错误:

>>> from schedule.models import Task
Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "/home/teelf/projects/schedule/server/schedule/models.py", line 14, in <module>
    class User(Base):
  File "/home/teelf/projects/schedule/server/venv/lib/python3.4/site-packages/flask_sqlalchemy/__init__.py", line 536, in __init__
    DeclarativeMeta.__init__(self, name, bases, d)
  File "/home/teelf/projects/schedule/server/venv/lib/python3.4/site-packages/sqlalchemy/ext/declarative/api.py", line 55, in __init__
    _as_declarative(cls, classname, cls.__dict__)
  File "/home/teelf/projects/schedule/server/venv/lib/python3.4/site-packages/sqlalchemy/ext/declarative/base.py", line 254, in _as_declarative
    **table_kw)
  File "/home/teelf/projects/schedule/server/venv/lib/python3.4/site-packages/sqlalchemy/sql/schema.py", line 393, in __new__
    "existing Table object." % key)
sqlalchemy.exc.InvalidRequestError: Table 'user' is already defined for this MetaData instance.  Specify 'extend_existing=True' to redefine options and columns
 on an existing Table object.

我该如何解决这个问题？

代码:

管理.py:

#!/usr/bin/env python

import os, sys

sys.path.append(os.path.abspath(os.path.join(os.path.dirname(__file__), '..')))

from flask.ext.migrate import Migrate, MigrateCommand
from flask.ext.script import Manager

from server import create_app
from database import db


app = create_app("config")

migrate = Migrate(app, db)
manager = Manager(app)

manager.add_command("db", MigrateCommand)

if __name__ == "__main__":
    manager.run()

__init__.py:

from flask import Flask

from flask.ext.login import LoginManager

from database import db
from api import api
from server.schedule.controllers import mod_schedule


def create_app(config):
    # initialize Flask
    app = Flask(__name__)

    # load configuration file
    app.config.from_object(config)

    # initialize database
    db.init_app(app)

    api.init_app(app)

    # initialize flask-login
    login_manager = LoginManager(app)

    # register blueprints
    app.register_blueprint(mod_schedule)

    return app

数据库.py:

from flask.ext.sqlalchemy import SQLAlchemy


db = SQLAlchemy()

模型.py:

from sqlalchemy.dialects.postgresql import UUID

from database import db


class Base(db.Model):
    __abstract__ = True

    id = db.Column(UUID, primary_key=True)


class User(Base):
    __tablename__ = "user"

    username = db.Column(db.String)
    password = db.Column(db.String)
    first_name = db.Column(db.String)
    last_name = db.Column(db.String)
    authenticated = db.Column(db.Boolean, default=False)

    def __init__(self, first_name, last_name, username):
        self.first_name = first_name
        self.last_name = last_name
        self.username = username

    def is_active(self):
        """ All users are active """
        return True

    def get_id(self):
        return self.username

    def is_authenticated(self):
        return self.authenticated

    def is_anonymous(self):
        """ Anonymous users are not supported"""
        return False

controllers.py:

from flask import Blueprint

from flask.ext.restful import reqparse, Resource

from api import api
from server.schedule.models import User


mod_schedule = Blueprint("schedule",  __name__, url_prefix="/schedule")


class Task(Resource):
    def put(self):
        pass

    def get(self):
        pass

    def delete(self):
        pass


api.add_resource(Task, "/tasks/<int:id>", endpoint="task")

Answer 1

尝试添加

 __table_args__ = {'extend_existing': True} 

到 __tablename__= 下的用户类

干杯