Python - 从纯文本邮件中提取正文

Question

我只想提取消息正文并将其返回。我可以过滤字段并显示代码段而不是正文。

def GetMimeMessage(service, user_id, msg_id):
    try:
            message = service.users().messages().get(userId=user_id, id=msg_id, format='raw').execute()
            print 'Message snippet: %s' % message['snippet']
            msg_str = base64.urlsafe_b64decode(message['raw'].encode('ASCII'))
            mime_msg = email.message_from_string(msg_str)
            return mime_msg
    except errors.HttpError, error:
            print 'An error occurred: %s' % error

https://developers.google.com/gmail/api/v1/reference/users/messages/get

Answer 1

谢谢。所以经过一些修改，这里的解决方案:

def GetMessageBody(service, user_id, msg_id):
    try:
            message = service.users().messages().get(userId=user_id, id=msg_id, format='raw').execute()
            msg_str = base64.urlsafe_b64decode(message['raw'].encode('ASCII'))
            mime_msg = email.message_from_string(msg_str)
            messageMainType = mime_msg.get_content_maintype()
            if messageMainType == 'multipart':
                    for part in mime_msg.get_payload():
                            if part.get_content_maintype() == 'text':
                                    return part.get_payload()
                    return ""
            elif messageMainType == 'text':
                    return mime_msg.get_payload()
    except errors.HttpError, error:
            print 'An error occurred: %s' % error