gpt4 book ai didi

python - 如何使用 paramiko.RSAKey.from_private_key()?

转载 作者:太空狗 更新时间:2023-10-29 18:21:26 24 4
gpt4 key购买 nike

知道如何使用 paramiko.RSAKey.from_private_key() 函数吗?

我知道有一个 from_private_key_file(),但我有兴趣使用一个函数来解析私钥(如下所示)并将该私钥用于 SSHClient.

私钥(示例):

-----BEGIN RSA PRIVATE KEY-----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\npneDFVvwgezCWoDauxNDzu7Nl55qPJsmvfKZ+SKvCajrhQw==\n-----END RSA PRIVATE KEY-----\n

我想运行的代码:

import paramiko
ssh = paramiko.SSHClient()
# how do I pass in the private_key, when my private_key (shown above) is in string?
mykey = paramiko.RSAKey.from_private_key(private_key)
ssh.connect('192.168.1.2', username = 'vinod', pkey = mykey)

非常感谢。

最佳答案

Lev 的方法对我有用:

>>> import paramiko
>>> f = open('/path/to/key.pem','r')
>>> s = f.read()
>>> import StringIO
>>> keyfile = StringIO.StringIO(s)
>>> mykey = paramiko.RSAKey.from_private_key(keyfile)
>>> ssh.set_missing_host_key_policy(paramiko.AutoAddPolicy())
>>> ssh.connect('myserver.compute-1.amazonaws.com', username='ubuntu', pkey=mykey)
>>> stdin, stdout, stderr = ssh.exec_command('uptime')
>>> stdout.readlines()
[' 19:21:10 up 24 days, 42 min, 1 user, load average: 0.14, 0.06, 0.05\n']

关于python - 如何使用 paramiko.RSAKey.from_private_key()?,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/9963391/

24 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com