python - 如何在 Django 休息 View 中使用 login_required

Question

我正在尝试在特定 View 中使用自定义登录 url

@login_required(login_url='/account/login/')
class home(APIView):
    renderer_classes = (TemplateHTMLRenderer,)

    def get(self, request, format=None):
        template = get_template(template_name='myapp/template.html')
        return Response({}, template_name=template.template.name)

但回溯显示

File "django/core/handlers/base.py", line 132, in get_response
    response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "django/contrib/auth/decorators.py", line 22, in _wrapped_view
    return view_func(request, *args, **kwargs)
TypeError: __init__() takes exactly 1 argument (2 given)

是否可以在基于类的 View 中使用自定义 login_required？

谢谢!

Answer 1

我认为您正在搜索 django rest framework APIView；在这里你可以使用权限类；请参阅此文档 http://www.django-rest-framework.org/api-guide/permissions/

添加到seetings.py

REST_FRAMEWORK = {
'DEFAULT_PERMISSION_CLASSES': (
    'rest_framework.permissions.IsAuthenticated',
)
}
from rest_framework.permissions import IsAuthenticated

class home(APIView):
   renderer_classes = (TemplateHTMLRenderer,)
   permission_classes = (IsAuthenticated,)

   def get(self, request, format=None):
       template = get_template(template_name='myapp/template.html')
       return Response({}, template_name=template.template.name)