python - 查找列表的最小值、最大值和平均值

Question

我很难弄清楚如何从列表中找到最小值例如

somelist = [1,12,2,53,23,6,17]

如何通过定义 (def) 函数找到此列表的最小值和最大值

我不想使用内置函数min

Answer 1

from __future__ import division

somelist =  [1,12,2,53,23,6,17] 
max_value = max(somelist)
min_value = min(somelist)
avg_value = 0 if len(somelist) == 0 else sum(somelist)/len(somelist)

如果您想手动找到最小值作为函数:

somelist =  [1,12,2,53,23,6,17] 

def my_min_function(somelist):
    min_value = None
    for value in somelist:
        if not min_value:
            min_value = value
        elif value < min_value:
            min_value = value
    return min_value

Python 3.4 引入了 statistics包，它提供 mean 和其他统计数据:

from statistics import mean, median

somelist =  [1,12,2,53,23,6,17]
avg_value = mean(somelist)
median_value = median(somelist)