rest - 使用 Angular 下载 zip 文件

Question

现在已经有好几个小时了，因为我正在尝试弄清楚如何使用 Angular 下载 zip 文件。下载的文件比原始文件小。我点击了这个链接 How do I download a file with Angular2 .

我不是简单地使用 <a>用于身份验证原因的下载标记。

服务

 downloadfile(filePath: string){
        return this.http
            .get( URL_API_REST + 'downloadMaj?filePath='+ filePath)
            .map(res => new Blob([res], {type: 'application/zip'}))
    }

组件

downloadfileComponent(filePath: string){
        this.appService.downloadfile(filePath)
            .subscribe(data => this.getZipFile(data)),
                error => console.log("Error downloading the file."),
                () => console.log('Completed file download.');
    }


getZipFile(data: any){
        var a: any = document.createElement("a");
        document.body.appendChild(a);

        a.style = "display: none";
        var blob = new Blob([data], { type: 'application/zip' });

        var url= window.URL.createObjectURL(blob);

        a.href = url;
        a.download = "test.zip";
        a.click();
        window.URL.revokeObjectURL(url);

    }

休息API

public void downloadMaj(@RequestParam(value = "filePath") String filePath, HttpServletResponse response) {

        System.out.println("downloadMaj");
        File fichierZip = new File(filePath);

        try {
            System.out.println("nom du fichier:" + fichierZip.getName());
            InputStream inputStream = new FileInputStream(fichierZip);

            response.addHeader("Content-Disposition", "attachment; filename="+fichierZip.getName());
            response.setHeader("Content-Type", "application/octet-stream");

            org.apache.commons.io.IOUtils.copy(inputStream, response.getOutputStream());
            response.getOutputStream().flush();
        } catch (FileNotFoundException e) {
            e.printStackTrace();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }

谁能说出为什么没有下载所有文件？

已解决

downloadfile(filePath: string) {
        return this.http
          .get( URL_API_REST + 'download?filePath=' + filePath, {responseType: ResponseContentType.ArrayBuffer})
          .map(res =>  res)
      }

private getZipFile(data: any) {
    const blob = new Blob([data['_body']], { type: 'application/zip' });

    const a: any = document.createElement('a');
    document.body.appendChild(a);

    a.style = 'display: none';    
    const url = window.URL.createObjectURL(blob);
    a.href = url;
    a.download = test.zip;
    a.click();
    window.URL.revokeObjectURL(url);

  }

Answer 1

1. 在responseType中你需要分配一个字符串，在本例中是arraybuffer (Angular 5+)

downloadFile(filename: string) {
  return this.http.get(URL_API_REST + 'download?filename=' + filename, {
    responseType: 'arraybuffer'
  });
}

1. 我们可以使用下一个代码创建一个窗口来直接下载我们的文件:

this.myService.downloadFile(filename).subscribe(data => {
  const blob = new Blob([data], {
    type: 'application/zip'
  });
  const url = window.URL.createObjectURL(blob);
  window.open(url);
});