angular - 如何在 AngularFire/TypeScript 中访问 FirebaseError 的 "code"属性？

Question

FirebaseError has a "code" property ，但是你如何在 promise 的 catch 方法中读取它？以下抛出 TypeScript 错误:Property 'code' does not exist on type 'Error'.

this.af.database
.object(`/some/path`)
.set(newObj)
.then(data => {
  console.log('success');
})
.catch(err => {
  // Property 'code' does not exist on type 'Error'.
  console.log(`code`, err.code);
});

Answer 1

要访问代码属性，您需要导入 firebase 并将您的错误指定为 firebase.FirebaseError 类型，如下所示:

import { AngularFire } from 'angularfire2';
import firebase from 'firebase';

...

constructor(
  private af: AngularFire
) {}

...

this.af.database
.object(`/some/path`)
.set(newObj)
.then(data => {
  console.log('success');
})
.catch( (err: firebase.FirebaseError) => {
  // Give your error the firebase.FirebaseError type and
  // you'll have access to all the FirebaseError properties
  console.log(`code`, err.code);
  console.log(`message`, err.message);
  console.log(`name`, err.name);
  console.log(`stack`, err.stack);
});