angular - 如何在 RxJS 5.5 中捕获错误

Question

我正在使用 Angular 5 和 RXJS 5.5

在我可以做这样的事情之前

getProjectInfo(id): Observable<any> {
    const URL = `${this.API}/${id}`;
    return this.http.get(URL)
      .pipe(map(res => res)),
      catchError(this.handleServerError);
}

handleServerError(error: any) {
    console.log(error.error || error.json() || error);
    return Observable.throw(error.error || error.json() || error || 'Server error');
}

但是现在我得到了这个错误

Error:(21, 5) TS2322:Type 'UnaryFunction<Observable<{}>, Observable<any>>' is not assignable to type 'Observable<any>'.
  Property '_isScalar' is missing in type 'UnaryFunction<Observable<{}>, Observable<any>>'.

这个我也试过

getProjectInfo(id): Observable<any> {
    const URL = `${this.API}/${id}`;
    return this.http.get(URL)
      .pipe(map(res => res)),
      catchError(err => this.handleError('getProjInfo', URL));
}
private handleError(method: String, URL: string): any {
  return (err: any) => {
    const errMsg = `error in ${method}() retrieving ${URL}`;
    console.log(`${errMsg}:`, err);
    if (err instanceof HttpErrorResponse) {
      console.log(`status: ${err.status}, ${err.statusText}`);
    }
    return Observable.throw(errMsg);
  };
}

我做错了什么？

Answer 1

请记住您的括号。您返回 pipe 结果和 catchEror 结果除以 ,:

return this.http.get(URL)
  .pipe(map(res => res)),
  catchError(this.handleServerError);

将一个括号放在自己的位置:

return this.http.get(URL)
  .pipe(
    map(res => res),
    catchError(this.handleServerError)
  );