Angular 分量进入传单弹出窗口

Question

无法弄清楚如何将组件生成到传单弹出窗口中。我试过两件事:

首先，将组件选择器集成到 html 中，但看起来 angular 没有编译它:

    let my geojson = L.geoJSON(data, {
        onEachFeature: (feature, layer) => {
            let popup = L.popup().setContent('<app-component-detail></app-component-detail>');
            layer.on({
                click: () => {
                    layer.bindPopup(popup);
                }
            })
        }
    }).addTo(map);

当我点击 map 上的一个点时，弹出窗口是空的。

然后我考虑使用“resolveComponentFactory”将组件生成到 ViewContainerRef 中。如果我用 @ViewChild 调用我的 View 元素，它会很好地工作:

模板:

<div #myContainer></div>

逻辑:

@ViewChild('myContainer', { read: ViewContainerRef } ) myContainer: ViewContainerRef;
private generatedComponent= this.componentFactoryResolver.resolveComponentFactory(componentDetail);
let my geojson = L.geoJSON(data, {
    onEachFeature: (feature, layer) => {
        layer.on({
            click: () => {
                this.myContainer.createComponent(this.generatedComponent);
            }
        })
    }
}).addTo(map);

现在我想将我的组件直接生成到弹出窗口中。我想我需要在弹出窗口的内容中设置一个 ViewContainerRef。类似的东西:

@ViewChild('popup', { read: ViewContainerRef } ) popup: ViewContainerRef;
private generatedComponent= this.componentFactoryResolver.resolveComponentFactory(componentDetail);
let my geojson = L.geoJSON(data, {
    onEachFeature: (feature, layer) => {
        let popup = L.popup().setContent('<div #popup></div>');
        layer.on({
            click: () => {
                layer.bindPopup(popup);
                this.popup.createComponent(this.generatedComponent);
            }
        })
    }
}).addTo(map);

编辑:这是我如何转置这个 solution到 leaflet.js

    let geojson = L.geoJSON(data, {
  style: () => defaultStyle,
  onEachFeature: (feature, layer) => {
    let popup = L.popup();
    layer.on({
      click: () => {
        this.zone.run( () => {

          if(this.componentRef){
            this.componentRef.destroy();
          }
          const compFactory = this.componentFactoryResolver.resolveComponentFactory(componentDetailmponent);
          this.componentRef = compFactory.create(this.injector);

          if (this.appRef['attachView']) { // since 2.3.0
           this.appRef['attachView'](this.componentRef.hostView);
           this.componentRef .onDestroy(() => {
             this.appRef['detachView'](this.componentRef.hostView);
          });
         } else {
          this.appRef['registerChangeDetector'](this.componentRef.changeDetectorRef);
          this.componentRef.onDestroy(() => {
            this.appRef['unregisterChangeDetector'](this.componentRef.changeDetectorRef);
          });
          }

          let div = document.createElement('div');
          div.appendChild(this.componentRef.location.nativeElement);
          popup.setContent(div);
        }
      )

      }
    });
    layer.bindPopup(popup);
  }
});

Answer 1

这是一个有效的解决方案:

创建组件

component = this.resolver.resolveComponentFactory(PopupComponent).create(this.injector);

将 NG 组件用作 HTML:

component.location.nativeElement

例如:

this.bindPopup(this.component.location.nativeElement);

地点:

• 解析器:ComponentFactoryResolver -> 来自“@angular/core”；
• 注入(inject)器:注入(inject)器 -> 来自“@angular/core”；

记得添加'app.module.ts':

entryComponents: [PopupComponent]

额外

• 必须通知 Angular 关于“更改”，调用:

  component.changeDetectorRef.detectChanges()

• 如果您想在弹出窗口中使用输入字段:

  DomEvent.disableClickPropagation(this.component.location.nativeElement);

:)