gpt4 book ai didi

python - Pyqt5 qthread + 信号不工作 + gui 卡住

转载 作者:太空狗 更新时间:2023-10-29 17:52:19 30 4
gpt4 key购买 nike

我正在尝试使用 imap lib 制作一个邮箱检查器,它在没有 gui 的情况下与 python、队列和多线程一起工作得很好。

但是当我尝试放置一个 gui 时,我制作的每个功能都会让 gui 卡住直到完成。

我尝试了各种文档(添加 qthread、signal、cursorr 等)和教程中的很多东西,但没有一个对我有用。

谁能帮助我理解如何在运行函数时设置文本或将文本附加到 QtextEdit,因为它只有在完成后才能工作。

这是我的代码:

class Checker(QtCore.QThread):
signal = QtCore.pyqtSignal(object)

def __init__(self, lignesmailtocheck):
QtCore.QThread.__init__(self)
self.lignesmailtocheck = lignesmailtocheck

def run(self):
lignemailtocheck = self.lignesmailtocheck.strip()
maillo, passo = lignemailtocheck.split(":",1)
debmail, finmail = maillo.split("@",1)
setimap =["oultook.com:imap-mail.outlook.com", "gmail.com:imap.gmail.com"]
for lignesimaptocheck in sorted(setimap):
ligneimaptocheck = lignesimaptocheck.strip()
fai, imap = ligneimaptocheck.split(":",1)
if finmail == fai:
passo0 = passo.rstrip()
try :
mail = imaplib.IMAP4_SSL(imap)
mail.login(maillo, passo)
mailboxok = open("MailBoxOk.txt", "a+", encoding='utf-8', errors='ignore')
mailboxok.write(maillo+":"+passo+"\n")
mailboxok.close()
totaly = maillo+":"+passo0+":"+imap
print(maillo+":"+passo+"\n")

self.send_text.emit(totaly)
time.sleep(1)
except imaplib.IMAP4.error:
print ("LOGIN FAILED!!! ")
class Ui_Form(object):
def setupUi(self, Form):
Form.setObjectName("Form")
Form.resize(400, 300)

self.pushButton = QtWidgets.QPushButton(Form)
self.pushButton.setGeometry(QtCore.QRect(150, 210, 75, 23))
self.pushButton.setObjectName("pushButton")
self.pushButton.clicked.connect(self.gogogo)

self.openliste = QtWidgets.QToolButton(Form)
self.openliste.setGeometry(QtCore.QRect(40, 110, 71, 21))
self.openliste.setObjectName("openliste")

self.textEdit = QtWidgets.QTextEdit(Form)
self.textEdit.setGeometry(QtCore.QRect(170, 50, 201, 121))
self.textEdit.setObjectName("textEdit")

self.progressBar = QtWidgets.QProgressBar(Form)
self.progressBar.setGeometry(QtCore.QRect(10, 260, 381, 23))
self.progressBar.setValue(0)
self.progressBar.setObjectName("progressBar")

self.retranslateUi(Form)
QtCore.QMetaObject.connectSlotsByName(Form)

def retranslateUi(self, Form):
_translate = QtCore.QCoreApplication.translate
Form.setWindowTitle(_translate("Form", "Form"))
self.pushButton.setText(_translate("Form", "PushButton"))
self.openliste.setText(_translate("Form", "..."))

def gogogo(self):

mailtocheck = open('File/toCheck.txt', 'r', encoding='utf-8', errors='ignore').readlines()
setmailtocheck = set(mailtocheck)
for lignesmailtocheck in sorted(setmailtocheck):
checker = Checker(lignesmailtocheck)

thread = QThread()
checker.moveToThread(thread)
# connections after move so cross-thread:
thread.started.connect(checker.run)
checker.signal.connect(self.checkedok)
thread.start()

def checkedok(self, data):
print(data)
self.textEdit.append(data)
if __name__ == "__main__":
app = QtWidgets.QApplication(sys.argv)
Form = QtWidgets.QWidget()
ui = Ui_Form()
ui.setupUi(Form)
Form.show()
sys.exit(app.exec_())

最佳答案

由于在 PyQt 中使用 QThread 时经常遇到类似问题,与您的类似,这里有一个示例来说明如何在 PyQt 中正确使用线程。我希望它可以作为类似问题的 goto-answer 有用,所以我花了比平时多一点的时间来准备这个。

该示例创建了许多工作对象,这些工作对象在非主线程中执行并通过 Qt 的异步信号与主(即 GUI)线程通信。

import time
import sys

from PyQt5.QtCore import QObject, QThread, pyqtSignal, pyqtSlot
from PyQt5.QtWidgets import QApplication, QPushButton, QTextEdit, QVBoxLayout, QWidget


def trap_exc_during_debug(*args):
# when app raises uncaught exception, print info
print(args)


# install exception hook: without this, uncaught exception would cause application to exit
sys.excepthook = trap_exc_during_debug


class Worker(QObject):
"""
Must derive from QObject in order to emit signals, connect slots to other signals, and operate in a QThread.
"""

sig_step = pyqtSignal(int, str) # worker id, step description: emitted every step through work() loop
sig_done = pyqtSignal(int) # worker id: emitted at end of work()
sig_msg = pyqtSignal(str) # message to be shown to user

def __init__(self, id: int):
super().__init__()
self.__id = id
self.__abort = False

@pyqtSlot()
def work(self):
"""
Pretend this worker method does work that takes a long time. During this time, the thread's
event loop is blocked, except if the application's processEvents() is called: this gives every
thread (incl. main) a chance to process events, which in this sample means processing signals
received from GUI (such as abort).
"""
thread_name = QThread.currentThread().objectName()
thread_id = int(QThread.currentThreadId()) # cast to int() is necessary
self.sig_msg.emit('Running worker #{} from thread "{}" (#{})'.format(self.__id, thread_name, thread_id))

for step in range(100):
time.sleep(0.1)
self.sig_step.emit(self.__id, 'step ' + str(step))

# check if we need to abort the loop; need to process events to receive signals;
app.processEvents() # this could cause change to self.__abort
if self.__abort:
# note that "step" value will not necessarily be same for every thread
self.sig_msg.emit('Worker #{} aborting work at step {}'.format(self.__id, step))
break

self.sig_done.emit(self.__id)

def abort(self):
self.sig_msg.emit('Worker #{} notified to abort'.format(self.__id))
self.__abort = True


class MyWidget(QWidget):
NUM_THREADS = 5

# sig_start = pyqtSignal() # needed only due to PyCharm debugger bug (!)
sig_abort_workers = pyqtSignal()

def __init__(self):
super().__init__()

self.setWindowTitle("Thread Example")
form_layout = QVBoxLayout()
self.setLayout(form_layout)
self.resize(400, 800)

self.button_start_threads = QPushButton()
self.button_start_threads.clicked.connect(self.start_threads)
self.button_start_threads.setText("Start {} threads".format(self.NUM_THREADS))
form_layout.addWidget(self.button_start_threads)

self.button_stop_threads = QPushButton()
self.button_stop_threads.clicked.connect(self.abort_workers)
self.button_stop_threads.setText("Stop threads")
self.button_stop_threads.setDisabled(True)
form_layout.addWidget(self.button_stop_threads)

self.log = QTextEdit()
form_layout.addWidget(self.log)

self.progress = QTextEdit()
form_layout.addWidget(self.progress)

QThread.currentThread().setObjectName('main') # threads can be named, useful for log output
self.__workers_done = None
self.__threads = None

def start_threads(self):
self.log.append('starting {} threads'.format(self.NUM_THREADS))
self.button_start_threads.setDisabled(True)
self.button_stop_threads.setEnabled(True)

self.__workers_done = 0
self.__threads = []
for idx in range(self.NUM_THREADS):
worker = Worker(idx)
thread = QThread()
thread.setObjectName('thread_' + str(idx))
self.__threads.append((thread, worker)) # need to store worker too otherwise will be gc'd
worker.moveToThread(thread)

# get progress messages from worker:
worker.sig_step.connect(self.on_worker_step)
worker.sig_done.connect(self.on_worker_done)
worker.sig_msg.connect(self.log.append)

# control worker:
self.sig_abort_workers.connect(worker.abort)

# get read to start worker:
# self.sig_start.connect(worker.work) # needed due to PyCharm debugger bug (!); comment out next line
thread.started.connect(worker.work)
thread.start() # this will emit 'started' and start thread's event loop

# self.sig_start.emit() # needed due to PyCharm debugger bug (!)

@pyqtSlot(int, str)
def on_worker_step(self, worker_id: int, data: str):
self.log.append('Worker #{}: {}'.format(worker_id, data))
self.progress.append('{}: {}'.format(worker_id, data))

@pyqtSlot(int)
def on_worker_done(self, worker_id):
self.log.append('worker #{} done'.format(worker_id))
self.progress.append('-- Worker {} DONE'.format(worker_id))
self.__workers_done += 1
if self.__workers_done == self.NUM_THREADS:
self.log.append('No more workers active')
self.button_start_threads.setEnabled(True)
self.button_stop_threads.setDisabled(True)
# self.__threads = None

@pyqtSlot()
def abort_workers(self):
self.sig_abort_workers.emit()
self.log.append('Asking each worker to abort')
for thread, worker in self.__threads: # note nice unpacking by Python, avoids indexing
thread.quit() # this will quit **as soon as thread event loop unblocks**
thread.wait() # <- so you need to wait for it to *actually* quit

# even though threads have exited, there may still be messages on the main thread's
# queue (messages that threads emitted before the abort):
self.log.append('All threads exited')


if __name__ == "__main__":
app = QApplication([])

form = MyWidget()
form.show()

sys.exit(app.exec_())

理解 PyQt 中的多线程编程所必需的主要概念如下:

  • Qt 线程有自己的事件循环(特定于每个线程)。主线程,又名 GUI 线程,也是一个 QThread,它的事件循环由该线程管理。
  • 线程之间的信号通过接收线程的事件循环进行(异步)传输。因此,GUI 或任何线程的响应能力 = 处理事件的能力。例如,如果一个线程在函数循环中很忙,它就不能处理事件,所以在函数返回之前它不会响应来自 GUI 的信号。
  • 如果线程中的工作对象(方法)可能必须根据来自 GUI 的信号更改其操作过程(例如,中断循环或等待),它必须调用 processEvents() QApplication 实例上的。这将允许 QThread 处理事件,从而调用槽以响应来自 GUI 的异步信号。请注意,QApplication.instance().processEvents() 似乎在每个线程上调用 processEvents(),如果不需要,则调用 QThread.currentThread()。 processEvents() 是一个有效的替代方法。
  • 调用 QThread.quit() 不会立即退出其事件循环:它必须等待当前正在执行的槽(如果有)返回。因此,一旦线程被告知退出,您就必须对其执行 wait() 操作。因此,中止工作线程通常涉及向它发出信号(通过自定义信号)以停止它正在做的任何事情:这需要 GUI 对象上的自定义信号,该信号与工作槽的连接,并且工作线程的工作方法必须调用线程的 processEvents() 允许发出的信号在工作时到达插槽。

关于python - Pyqt5 qthread + 信号不工作 + gui 卡住,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/41526832/

30 4 0
Copyright 2021 - 2024 cfsdn All Rights Reserved 蜀ICP备2022000587号
广告合作:1813099741@qq.com 6ren.com