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python - 如何在 Pandas 数据框中展开列

转载 作者:太空狗 更新时间:2023-10-29 17:42:10 27 4
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我有以下 Pandas 数据框:

import pandas as pd
import numpy as np
df = pd.DataFrame({
'fc': [100,100,112,1.3,14,125],
'sample_id': ['S1','S1','S1','S2','S2','S2'],
'gene_symbol': ['a', 'b', 'c', 'a', 'b', 'c'],
})

df = df[['gene_symbol', 'sample_id', 'fc']]
df

产生这个:

Out[11]:
gene_symbol sample_id fc
0 a S1 100.0
1 b S1 100.0
2 c S1 112.0
3 a S2 1.3
4 b S2 14.0
5 c S2 125.0

我怎样才能传播 sample_id 以便最终得到这个:

gene_symbol    S1   S2
a 100 1.3
b 100 14.0
c 112 125.0

最佳答案

使用pivotunstack :

#df = df[['gene_symbol', 'sample_id', 'fc']]
df = df.pivot(index='gene_symbol',columns='sample_id',values='fc')
print (df)
sample_id S1 S2
gene_symbol
a 100.0 1.3
b 100.0 14.0
c 112.0 125.0

df = df.set_index(['gene_symbol','sample_id'])['fc'].unstack(fill_value=0)
print (df)
sample_id S1 S2
gene_symbol
a 100.0 1.3
b 100.0 14.0
c 112.0 125.0

但如果重复,需要pivot_table or aggregate with groupby or , mean 可以改成 sum, median, ...:

df = pd.DataFrame({
'fc': [100,100,112,1.3,14,125, 100],
'sample_id': ['S1','S1','S1','S2','S2','S2', 'S2'],
'gene_symbol': ['a', 'b', 'c', 'a', 'b', 'c', 'c'],
})
print (df)
fc gene_symbol sample_id
0 100.0 a S1
1 100.0 b S1
2 112.0 c S1
3 1.3 a S2
4 14.0 b S2
5 125.0 c S2 <- same c, S2, different fc
6 100.0 c S2 <- same c, S2, different fc
df = df.pivot(index='gene_symbol',columns='sample_id',values='fc')

ValueError: Index contains duplicate entries, cannot reshape

df = df.pivot_table(index='gene_symbol',columns='sample_id',values='fc', aggfunc='mean')
print (df)
sample_id S1 S2
gene_symbol
a 100.0 1.3
b 100.0 14.0
c 112.0 112.5

df = df.groupby(['gene_symbol','sample_id'])['fc'].mean().unstack(fill_value=0)
print (df)
sample_id S1 S2
gene_symbol
a 100.0 1.3
b 100.0 14.0
c 112.0 112.5

编辑:

为了清理,将columns name 设置为Nonereset_index :

df.columns.name = None
df = df.reset_index()
print (df)
gene_symbol S1 S2
0 a 100.0 1.3
1 b 100.0 14.0
2 c 112.0 112.5

关于python - 如何在 Pandas 数据框中展开列,我们在Stack Overflow上找到一个类似的问题: https://stackoverflow.com/questions/43973999/

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